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Bess [88]
3 years ago
8

Help Please Just with part B...PLEASE!!!

Mathematics
1 answer:
dsp733 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Note that \frac{6}{8} can be simplified by dividing the numerator and denominator by 2, so that

\frac{6}{8} = \frac{3}{4} in simplest form

Thus parsley and scallions are the same amount. Ramon is correct.


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I need help with A-G,I,L,N<br>I hope yall have a merry Christmas ​
KonstantinChe [14]

Format of my answer:

[Problem letter] Parallel Lines

- Converse / Reason

!! I am not sure which / what converses you are using, but I gave the reasoning for it. If you see something similar, use the converses you know !!

[a] j & k

- If two lines intersected by a  transversal form congruent alternate interior angles, then the lines are parallel

[b] m & n

- If angles are supplementary in this placement, the lines are parallel

[c] l & n

- If angles are equal when they are corresponding, the lines are parallel

[d] l & m

- If two angles that are congruent are vertical, the lines are parallel

[e] j & k

- If two lines intersected by a  transversal form congruent corresponding angles, then the lines are parallel

[f] l & n

- If angles are supplementary in this placement, the lines are parallel

[g] l & n

- If two angles that are congruent are vertical, the lines are parallel

[h] -------

[i] l & n

- If two angles that are congruent are vertical, the lines are parallel

[j] -------

[k] -------

[l] j & k

- If two lines intersected by a  transversal form congruent corresponding angles, then the lines are parallel

[m] -------

[n] j & k

- If angles are supplementary in this placement, the lines are parallel

[o] -------

-> See attached for more information

Have a nice day! - hopefully these are mostly correct, been awhile since I've done this

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0
2 years ago
For a trapezoid with a height of 7 centimeters and base lengths of 6 centimeters and 10 centimeters, the area is
soldier1979 [14.2K]

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=10\\ h=7 \end{cases}\implies A=\cfrac{7(6+10)}{2} \\\\\\ A=\cfrac{7(16)}{2}\implies A=7(8)\implies A=56

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3 years ago
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