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AURORKA [14]
2 years ago
9

Simplify the expresión 8(-4+-3p)

Mathematics
1 answer:
zavuch27 [327]2 years ago
7 0

Answer:

-32-24p

Step-by-step explanation:

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A pond forms as water collects in a conical depression of radius a and depth h. Suppose that water flows in at a constant rate k
Scrat [10]

Answer:

a. dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

The rate of water entering - The rate of water leaving the pond.

Given

k = Rate of Water flows in

The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

Rate of volume of water in pond with time = k - ∝πr²

dV/dt = k - ∝πr² ----- equation 1

The volume of the conical pond is calculated by πr²L/3

Where L = height of the cone

L = hr/a where h is the height of water in the pond

So, V = πr²(hr/a)/3

V = πr³h/3a ------ Make r the subject of formula

3aV = πr³h

r³ = 3aV/πh

r = ∛(3aV/πh)

Substitute ∛(3aV/πh) for r in equation 1

dV/dt = k - ∝π(∛(3aV/πh))²

dV/dt = k - ∝π((3aV/πh)^⅓)²

dV/dt = K - ∝π(3aV/πh)^⅔

dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. Equilibrium depth of water

The equilibrium depth of water is when the differential equation is 0

i.e. dV/dt = K - ∝π(3a/πh)^⅔V^⅔ = 0

k - ∝π(3a/πh)^⅔V^⅔ = 0

∝π(3a/πh)^⅔V^⅔ = k ------ make V the subject of formula

V^⅔ = k/∝π(3a/πh)^⅔ -------- find the 3/2th root of both sides

V^(⅔ * 3/2) = k^3/2 / [∝π(3a/πh)^⅔]^3/2

V = (k^3/2)/[(∝π.π^-⅔(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝π^⅓(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝^3/2.π^½.(3a/h))]

V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. Condition that must be satisfied

If we continue adding water to the pond after the rate of water flow becomes 0, the pond will overflow.

i.e. dV/dt = k - ∝πr² but r = a and the rate is now ≤ 0.

So, we have

k - ∝πa² ≤ 0 ---- subtract k from both w

- ∝πa² ≤ -k divide both sides by - ∝

πa² ≥ k/∝

5 0
3 years ago
Complete the table to show the total distance walked in each case. Please use decimal notation for your answer.
Alex17521 [72]

Answer:

its i dont know

Step-by-step explanation:

7 0
3 years ago
What cross section shape is formed when the figure is cut as shown?
kirza4 [7]

Answer:

Triangle

Step-by-step explanation:

7 0
2 years ago
F(x) = 3x + 8; g(x) = 5x - 9<br> (a) Find (f + g)(x).
AysviL [449]

Answer: f(x) = 8x -1

Step-by-step explanation:

( f + g )x = 3x + 5x + 8 - 9

( f + g)x = 8x - 1

8 0
3 years ago
Find the values of a b and c for which the quadratic equation ax^2+bx+c=0 has the solutions -3 and 1
zavuch27 [327]
It may be easier to start from

.. a(x +3)(x -1) = 0
.. a(x^2 +2x -3) = 0

The quadratic
.. ax^2 +bx +c = 0 will have solutions -3 and 1 for ...

.. a ≠ 0
.. b = 2a
.. c = -3a
7 0
3 years ago
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