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GREYUIT [131]
4 years ago
6

Recall the definition of a polynomial expression. Find two polynomial expressions whose quotient, when simplified, is 1/x. Use t

hat division problem to determine whether polynomials are closed under division. Then describe how the other three operations—addition, subtraction, and multiplication—are different from division of polynomials.
Please help, thanks so much!!
Mathematics
2 answers:
nasty-shy [4]4 years ago
8 0

Answer:

Step-by-step explanation:

A polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.

Actually 1 and x both are polynomials. Therefore 1/x is already a quotient of polynomials.

Two polynomial expressions whose quotient, when simplified, is 1/x

x+1/x^2+x

Take the common of the denominator

x+1/x(x+1)

x+1 will be cancelled out by x+1

1/x

1/x is not a polynomial, so polynomials are not closed under division.

Polynomials are closed under addition, subtraction and multiplication. Addition and multiplication are associative and commutative.

There is an additive identity which is 0.

There is a multiplicative identity which is 1....

dezoksy [38]4 years ago
5 0

Answer:

Polynomials are not closed under division. Many examples can prove that they are not. Any division of polynomials that leaves a variable to the first or higher power in the denominator is not a polynomial because it has a variable with an exponent that is not a positive integer.

When we add or subtract two polynomials, we’re combining like terms, or terms with the same power of the same variable. Therefore, the exponents and variables don’t change. Only the coefficients of each term might change. This means that the result must be a polynomial, and therefore polynomials are closed under subtraction.

The product of polynomials can have the same original variables as the factors but with higher integer exponents. These products will also be polynomials.

Step-by-step explanation:

plato

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Andre has a summer job selling magazine subscriptions. He earns $25 per week plus $3 for every subscription he sells. Andre hope
Lelechka [254]

Answer:

C = 25 + 3n

Step-by-step explanation:

Andre has a summer job selling magazine subscriptions.

We are told that:

Andy earns $25 per week plus $3 for every subscription he sells.

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5 0
3 years ago
For what value of constant c is the function k(x) continuous at x = 0 if k =
nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

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5 0
2 years ago
Help would be much appreciated :)
makkiz [27]

Answer:

  • x = - 9

Step-by-step explanation:

<u>In order to find the vertical asymptotes make the denominator equal to zero and solve:</u>

  • 2x + 18 = 0
  • 2x = - 18
  • x = - 9

There is one vertical asymptote since the denominator is linear expression

6 0
2 years ago
Find the value of x. 14 and 15
MAVERICK [17]

Answer:

15) x=62

14) 19

Step-by-step explanation:

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