Answer:
Supersaturated.
Explanation:
Hello there!
In this case, according to this solubility chart, we infer that for NH3, the solubility starts at 90 grams of NH3 that are soluble in 100 g of water at 0 °C and ends in about 8 g in 100 g of water at 100 °C for a saturated solution.
However, since we are asked for the solubility of NH3 at 20 °C, we can see that, according to the table and the curve for NH3, about 52 g of NH3 are soluble in 100 g of water; thus, for the given 60 g of NH3, we will say that 8 grams will remain undissolved, and therefore, this solution will be supersaturated.
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Answer:
278 mL x 0.038 M = 10,564 mmol.
Using the molair mass of Fe2(SO4)3 to convert mmol to grams:
10,564 mmol / 1000 x 399,88 g/mol = 4,22 g Fe2(SO4)3.
1) Balanced chemical equation
8H2S +4O2 ---> S8 + 8H2O
2) Molar ratios
8 mol H2S : 4 mol O2 : 1 mol S8
3) Convert 50.0 grams of H2S into moles
moles = mass in grams / molar mass
molar mass H2S = 2*1g/mol + 32.1 g/mol = 34.1 g/mol
moles = 50.0 g / 34.1 g/mol = 1.466 moles H2S
4) Convert 60.0 g of O2 into moles
molar mass O2 = 2*16g/mol = 32.0g/mol
moles = 60.0g / 32.0 g = 1.875 moles O2
5) State limiting reagent
Theoretical ratio: 8 mol H2S / 4 mol O2 = 8/4 = 2/1 = 2
Actual ratio 1.466 mol H2S / 1.875 mol O2 < 2
=> H2S is the limiting reagent (it is consumed completely whilce some O2 remains unreacted).
6) Determine the moles of S8 produced from 1.466 moles H2S
1 mol S8 / 8 mol H2S * 1.466 mol H2S = 0.18325 mol S8
7) Convert 0.18325 mol S8 to mass
mass = number of moles * molar mass
molar mass S8 = 8 mol * 32.1g/mol = 256.8 g/mol
mass = 0.18325 mol * 256.8 g/mol = 47.1 grams
Answer: 47.1 g
Answer:
A. The ratio of the element in glucose is different than in ethanol
Explanation:
The compounds given are;
Glucose C₆H₁₂O₆
Ethanol C₂H₆O
The two compounds given are different from one another. But they have the same elemental composition.
Ethanol is made up of Carbon, hydrogen and Oxygen and so also, Glucose
Now,
The number of atoms in both compounds are different;
Number of atoms
C H O
Glucose 6 12 6
Ethanol 2 6 1
Answer:
4.10x10⁻³g.
4.10 mg.
Explanation:
Hello,
In this case, considering the given number, we can see it has two digits after the first nonzero digit that is four (4) which is also at the third decimal place, it means that the scientific notation has a negative power as it is at the left of the given zeros, therefore it is:
4.10x10⁻³g.
Moreover, since the proper prefix for the factor x10⁻³ is milli, the number with prefix is:
4.10 mg.
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