Answer:
Explanation:
If the enzyme active site is complementary to the substrate conformation rather than to the transition state, it is unlikely that the reaction will proceed and release a product, because the enzyme-substrate complex will be tightly bound (ΔG will raise).
On the other hand, when the enzyme active site is complementary to the transition state, the substrate will not be tightly bound and will be more prone to be transformed into the product (<u>ΔG will be lowered</u>) and afterward, be released.
The weak interactions (non-covalent bonds) will stabilize the energy of the transition state and reduce its energy, thus lowering the activation energy). If the transition state is stable, it will form more easily and<u> the reaction will be more likely to proceed.</u>
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It turns sugar into H2O and CO2. So I guess you could say it breaks down food to release energy.
Answer:D. In order to restore equilibrium, the reaction shifts right, towards products
Explanation:
1.59 moles
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Answer:
Its right you dont have to change anything
