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Nikolay [14]
3 years ago
14

All the questions to The power of advertising commonlit answers.

Chemistry
1 answer:
NemiM [27]3 years ago
8 0
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Compare the keys to periodic tables a and b to the key to the periodic table in your textbook. what other information is provide
lesya692 [45]
What the definition of each period and group and element and every valence electron
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Which phrase best summarizes how animals get water from the environment
adell [148]
What are the phrases to choose from?
6 0
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A sample of 40.0 mL of hydrogen is collected by water displacement at a temperature of 20 degrees Celcius. The barometer reads 7
Roman55 [17]

Answer : The volume of the hydrogen at STP is, 36.8 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 751 torr

P_2 = final pressure of gas at STP = 760 torr

V_1 = initial volume of gas = 40.0 mL

V_2 = final volume of gas at STP = ?

T_1 = initial temperature of gas = 20^oC=273+20=293K

T_2 = final temperature of gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{751torr\times 40.0mL}{293K}=\frac{760torr\times V_2}{273K}

V_2=36.8mL

Therefore, the volume of the hydrogen at STP is, 36.8 mL

6 0
3 years ago
A beach ball has a mass of 5 g and a volume of 20 cm3. What is the object's density?
ivann1987 [24]
Mass = 5 g

volume = 20 cm³

density = mass / volume

therefore:

D = m / V

D = 5 / 20

D = 0.25 g/cm³
3 0
4 years ago
g Green plants use light from the Sun to drive photosynthesis. Photosynthesis is a chemical reaction in which water and carbon d
LenaWriter [7]

Answer:

6.49g

Explanation:

Let's consider the balanced reaction for photosynthesis.

6 CO₂ + 6 H₂O = C₆H₁₂O₆ + 6 O₂

We can establish the following relations:

  • 1 mole of CO₂ has a mass of 44.01 g (MW 44.01)
  • The molar ratio of CO₂ to C₆H₁₂O₆ is 6:1.
  • 1 mole of C₆H₁₂O₆ has a mass of 180.16 g/mol.

The mass of glucose produced by the reaction of 9.51 g of carbon dioxide is:

9.51gCO_2 \times \frac{1molCO_2}{44.01gCO_2}  \times \frac{1molGlucose}{6molCO_2}  \times \frac{180.16gGlucose}{1molGlucose} = 6.49g Glucose

6 0
3 years ago
Read 2 more answers
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