Answer:
840
Step-by-step explanation:
Hi there!
Usually, this kind of problem asks us the perimeter rather than the area. But when talking on this grid on how many cms are necessary to construct one made up of 9 squares 1cm x1 cm. We need to check one thing: Some line segments will be used twice. So this is not a classical perimeter question.
1) So we either manually and carefully count it avoiding not doing it twice the same common line segments.
Or.
2) By just applying an algorithm, Where n is the <em>nxn</em> grid
So, for the 20x20 grid
Answer:
5,7, or 9
Step-by-step explanation:
a,b and c are the sides of a triangle if it satisfies:
a<b+c , b<a+c and c<b+a
Here, a=4 and b=7
We have to find c
i.e. all those c which satisfies:
4<7+c , 7<4+c and c<4+7=11
Answer:
The volume of a sphere can be approximated by cylinders. As the number of cylinders approaches infinity the total volume of all the cylinder approaches the actual volume of the sphere.
<span>The name of the shape graphed by the function r ^ 2 = 9
cos (2 theta) is called the “<u>lemniscate</u>”. A lemniscate is a
plane curve with a feature shape which consists of two loops that meet at a
central point. The curve is also sometimes called as the lemniscate of
Bernoulli. </span>
Explanation:
The
period of coskθ is 2π/k. In this case, k = 2 therefore the
period is π.
r ^ 2 = 9 cos 2θ ≥0 → cos 2θ ≥0. So easily
one period can be chosen as θ ∈
[0, π] wherein cos 2θ ≥0.
As cos(2(−θ)) = cos2θ, the graph is symmetrical about the initial line.
Also,
as cos (2(pi-theta) = cos 2theta, the graph is symmetrical about the
vertical θ = π/2
A
Table for half period [0,π4/] is
adequate for the shape in Quarter1
Use symmetry for the other three quarters:
(r, θ) : (0,3)(3/√√2,π/8)(3√2/2,π/6)(0,π/4<span>)</span>
The answer is is number 3
