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Colt1911 [192]
4 years ago
11

On a coordinate plane, a straight red line with a negative slope, labeled g of x, crosses the y-axis at (0, negative 7). A strai

ght blue line with a positive slope, labeled f of x, crosses the x-axis at (negative 1, 0) and the y-axis at (0, 2). Both lines intersect at (negative 3, negative 4). Which statement is true regarding the functions on the graph? f(–3) = g(–4) f(–4) = g(–3) f(–3) = g(–3) f(–4) = g(–4)

Mathematics
2 answers:
emmainna [20.7K]4 years ago
8 0

Answer:

f(-3)=g(-3)

Step-by-step explanation:

The graph shows two linear functions that intersect at (-3,-4).

The blue line is f(x).

At the point of intersection:

f(-3)=-4....eqn1

The blue line is g(x).

At the point of intersection

g(-3)=-4....eqn2

Equating both equations we get:

f(-3)=g(-3)

The statement that is true regarding the two functions is that:

f(-3)=g(-3)

Monica [59]4 years ago
5 0

Answer:

its the third answer

Step-by-step explanation:

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x^2 – 16x + 63 < 0

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