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boyakko [2]
3 years ago
11

Solve by completing the square: x2 + 3x – 9 = 0

Mathematics
2 answers:
IrinaK [193]3 years ago
4 0

Answer:

Step-by-step explanation:

x = 9/5

Ymorist [56]3 years ago
3 0

Answer:

\purple{  \boxed{\bold{x =  \frac{3 (\sqrt{5} - 1) }{2}}}} \: or \:   \red{  \boxed{\bold{x = \frac{ - 3 (\sqrt{5}  + 1) }{2}}}}

Step-by-step explanation:

{x}^{2}  + 3x - 9 = 0 \\  {x}^{2}  + 2. \frac{3}{2}x  = 9 \\  {x}^{2}  + 2. \frac{3}{2} x +  { \bigg (\frac{3}{2}  \bigg)}^{2}  = 9 + { \bigg (\frac{3}{2}  \bigg)}^{2} \\  \\  \bigg(x +  \frac{3}{2}  \bigg)^{2}  = 9 +  \frac{9}{4}  \\  \\ \bigg(x +  \frac{3}{2}  \bigg)^{2}  = \frac{45}{4}  \\  \\\bigg(x +  \frac{3}{2}  \bigg) =  \pm \sqrt{ \frac{45}{4} }  \\  \\\bigg(x +  \frac{3}{2}  \bigg) =  \pm { \frac{3 \sqrt{5} }{2} }  \\  \\ x = \pm { \frac{3 \sqrt{5} }{2} }  - \frac{3}{2} \\  \\ x =  \pm { \frac{3 \sqrt{5} - 3 }{2} }  \\  \\ x =  \frac{3 \sqrt{5} - 3 }{2} \: or \:  x =  \frac{ - 3 \sqrt{5} - 3 }{2} \\  \\  \purple{  \boxed{\bold{x =  \frac{3 (\sqrt{5} - 1) }{2}}}} \: or \:   \red{  \boxed{\bold{x = \frac{ - 3 (\sqrt{5}  + 1) }{2}}}}  \\

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