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Tema [17]
3 years ago
12

Explain angular momentum precession and give examples.

Physics
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:

T=\dfrac{d\left(I\omega\right)}{dt}

Explanation:

Angular momentum precision:

   We know that

Linear momentum P= m. v

Rate of change in linear momentum is called force.

Angular momentum L = I.ω

            L =  I.ω

Rate of change in angular momentum is called torque .

T=\dfrac{d\left(I\omega\right)}{dt}

This rate of change of angular momentum is called angular momentum precision.

Example of angular momentum:

1. Lets take a disc is connected to shaft ,When disc is rotating along its axis and shaft is also rotating .

2.When air plane take turn then they feel one torque this torque is nothing ,it is due to angular momentum precision.

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Why do temperatures on the moons surface vary ncyb more than temperatures on earth
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The moon has no atmosphere

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3 years ago
A 3858 N piano is to be pushed up a(n) 3.49 m frictionless plank that makes an angle of 31.6 ◦ with the horizontal. Calculate th
uranmaximum [27]
The work done will be equal to the potential energy of the piano at the final position

P.E=m.g.h

.consider the plank the hypotenuse of the right triangle formed with the ground
.let x be the angle with the ground=31.6°
.h be the side opposite to the angle x (h is the final height of the piano)
.let L be the length of the plank

sinx=opposite side / hypotenuse
= h/L

then h=L.sinx=3.49×sin31.6°=0.638m

weight w=m.g
m=w/g=3858/10=385.8kg

Consider Gravity g=10m/s2

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8 0
3 years ago
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Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end to
Pie

Answer:

Vc = 2.41 v

Explanation:

voltage (v) = 16 v

find the voltage between the ends of the copper rods .

applying the voltage divider theorem

Vc = V x (\frac{Rc}{Rc + Ri})

where

  • Rc = resistance of copper = \frac{ρl}{a}  (l = length , a = area, ρ = resistivity of copper)
  • Ri = resistance of iron = \frac{ρ₀l}{a}  (l = length , a = area, ρ₀ = resistivity of copper)

Vc =  V x (\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}})

Vc = V x (\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})})

Vc = V x (\frac{ρ}{ρ + ρ₀})

where

  • ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter
  • ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter

Vc = 16 x (\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}})

Vc = 2.41 v

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