The Initial height of the tire will be 0.32 m
<u>Explanation:</u>
<u>We have the formula,</u>
h=Vf^2/2g
h=V×f×f/2g
where Vf denotes the speed of the tire at the bottom of the swing
where g denotes the acceleration
due to the gravity
h=2.5×2.5=6.25
2×9.8 =19.8
h=6.25/19.8
h=0.32
The Initial height of the tire will be 0.32 m
The charge on the positive plate is 1.734*
C
Given,
V=9v, R=0.066m Gap(G)=2.0mm=0.0020m ∈=8.85*
We know C=∈ *
= 8.85*
*
=19.275*
F
Also, Q = C V = 19.275*
* 9 = 1.734*
C
<h3>Charge </h3>
When charged matter is exposed to an electromagnetic field, its electric charge—a property of matter—causes it to feel a force. A charge on an electric field might be positive or negative. Like and unlike charges are attracted to one another while being repelled by the other. Neutral describes a thing without any net charge. Electric charge is a conserved property; in an isolated system, the net charge, or the sum of the positive and negative charges, is constant. Subatomic particles transport electrical charge. The protons in atoms' nuclei carry positive charge in normal matter, while the electrons carry negative charge.
Learn more about charge here:
brainly.com/question/19886264
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Answer:
Yes
Explanation:
The cart will definitely behave differently because more weight is added to it.
In order to successfully push a cart, the applied force must exceed the force of the weight of the cart along with its constituents and the frictional force between the tyres and the floor.
<em>When more weights are added (the 2 packs of water bottles), it means that more force would be needed to overcome the opposing forces to the movement of the cart in order to successfully push the cart again.</em>
Answer: 244.05 J
Explanation:
To find speed at 30 m above the ground use equation:
V²=Vo²-2Gs
V0=31.4m/s
s=30m
G=9.81m/s²
-----------------------
V²=31.4²-2*9.81*30
V²=985.96+588.6
V²=1574.56
V=39.68m/s ---speed of arrow on 30 m obove the ground
Use equation for kinetic enrgy:
Ke=mV²/2
m=0.155kg
V=39.68m/s
-------------------------
Ke=0.155kg*(39.68m/s)²/2
Ke=0.155*1574.5/2
Ke=244.05J