Answer:
I believe that it is a irrational number.
Step-by-step explanation:
An irrational number is a number that cannot be written as a fraction with a num and denom that aren't equal to 0. These cannot be expressed as repeating decimals. -pi has all these traits, therefore it's irrational.
Answer:
A) {x < −2
{y ≤ −x − 2
Step-by-step explanation:
The first step is to treat these inequalities as Slope-Intercept equations, then graph them according to what you know about the <em>rate</em><em> </em><em>of </em><em>changes</em><em> </em>[<em>slopes</em>] of the lines. Then insert the inequality symbols later and figure out which line they get, based on their symbols:
Dashed Line → >, <
Solid Line → ≥, ≤
is the vertical line with a <em>less</em><em> </em><em>than</em><em> </em>sign, so it gets the <em>dashed</em><em> </em><em>line</em>,<em> </em>whereas the other line has a <em>less</em><em> </em><em>than</em><em> </em><em>or</em><em> </em><em>equal to</em><em> </em>sign, so this line gets the solid line.
I am joyous to assist you anytime.
Let
rA--------> radius of the circle R
rB-------> radius of the circle S
SA------> the area of the sector for circle R
SB------> the area of the sector for circle S
we have that
rA=3 ft
rB=6 ft
rA/rB=3/6----> 1/2----------->
rB/rA=2
SA=2π ft²
we know that
if Both circle A and circle B have a central angle , the square
of the ratio of the radius of circle A to the radius of circle B is equals to
the ratio of the area of the sector for circle A to the area of the sector for
circle B
(rA/rB) ^2=SA/SB-----> SB=SA*(rB/rA) ^2----> SB=(2) ^2*(2π)--->
SB----------- > 8π ft²
the answer is
the area of the sector for circle S is 8π ft²
Answer: 
Step-by-step explanation:
We can use the following formula to solve this exercise:

In this case "T" is the time in hours it takes to both taps fill the pool working together, "A" is the time in hours for the first tap filling the pool alone an "B" is the time in hours for the second tap filling the pool alone.
We can identify that:

Then, we must subsitute the known values into the formula:

And finally we must solve for "B".
Then we get:
