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egoroff_w [7]
4 years ago
14

If it takes one second to count two rice grains,calculate the time in years required to count a mole of rice grainrg.

Chemistry
1 answer:
Anuta_ua [19.1K]4 years ago
5 0
Mole is 6,022*10^23 

6,022 * 10^23 /2 (here are seconds) then /60 (minutes), then /60 (hours) /24 (days), then /365 (year) equals 9547818366311516,9965 years

every 4 years there's one day more in a year, so 9547818366311516,9965 /4 ( here are days) then / 365 = 6539601620761,31 years less.

the answer is 9547818366311516,9965 - 6539601620761,31 = 9541278764690755,6865 years to calculate the rice
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How many atoms are in 6.2 moles of aluminum?
Kazeer [188]
<span>6.2×6.022×<span>1023</span>=3.733×<span>1024</span></span><span> atoms.</span>
7 0
4 years ago
Producer gas is a fuel formed by passing air over red-hot coke (amorphous carbon). What mass of a producer gas that consists of
Karolina [17]

Producer gas is a fuel that is produced by burning biomass with an air deficit passed over red-hot coke (amorphous carbon). This gas is nothing but a mixture of gases such as hydrogen (H), carbon monoxide (CO), carbon dioxide (CO₂) and nitrogen (N₂).

The equation of producer gas is as follows -

                            CO₂ + 2N₂ (air) → CO + 2N₂

                            ΔH = -27.06 kcal

We know that,

1 Ton = 1000 kg

Mass of coke needed to form producer gas = 1.75 tons = 1750 kg

Given values,

Carbon monoxide (CO) = 25%  

Carbon dioxide (CO₂) = 5%

Nitrogen (N₂) = 70%

One mole of carbon dioxide reacts with two moles of nitrogen to form one mole of carbon monoxide and nitrogen (producer gas).

We know that, 1 ton (1000 kg) of coke produces 470 Nm³ of producer gas, i.e.

470 × 4.359 = 2048.73 kg

1000 kg of coke produces = 2048.73 kg of producer gas

∴ 1 kg of coke produces = 2048.73 ÷ 1000 kg of producer gas

∴ 1750 kg of coke produces = 2048.73 × 1750 / 1000 = 3585.28 kg of producer gas.

Percentage yield = 87%

                             = 3585.28 × 87/100

                             = 3119.19 kg of producer gas

                             = 3.44 tons

Learn more about coke here-

brainly.com/question/13105289

#SPJ4

7 0
2 years ago
How many grams of Fe can be produced when 6.50 g of Fe2O3 reacts?
AveGali [126]

Answer:

Mass of Fe produced = 4.468 g

Explanation:

Given data:

Mass of Fe produced = ?

Mass of Fe₂O₃ react = 6.50 g

Solution:

Chemical equation:

2Fe₂O₃        →     4Fe + 3O₂

Number of moles of Fe₂O₃ ;

Number of moles = mass/molar mass

Number of moles = 6.50 g/159.69 g/mol

Number of moles = 0.04 mol

Now we will compare the moles of iron and ironoxide.

                    Fe₂O₃             :             Fe

                         2                :              4

                       0.04             :             4/2×0.04 = 0.08 mol

Mass of iron produced:

Mass = number of moles × molar mass

Mass = 0.08 mol × 55.85 g/mol

Mass = 4.468 g

6 0
3 years ago
Mario believes he has found the reason that some things glow in the dark while others do not. What is the most important thing h
diamong [38]
B. <span>Develop experiments that can be repeated to test his theory.</span>
3 0
4 years ago
1. Perform calculations to determine the amount of 6.00x10-5 M stock solution needed to prepare 20.00 mL of 2.00x10-5 M dye solu
zhannawk [14.2K]

Answer:

1a. 6.70 ml of stock dye solution is required

1b. 10.0 ml of stock dye solution is required

1c. 4.00 ml of stock dye solution is required

Explanation:

1a. Using m₁v₁ = m₂v

6.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁵

v₁ = 4 * 10⁻⁴/6.00 * 10⁻⁵

v₁ = 6.70 mL of stock solution

Therefore, 6.70 ml of stock dye solution is required

b. Using m₁v₁ = m₂v

2.00 * 10⁻⁵ * v₁ = 20.0 * 1.00 * 10⁻⁵

v₁ = 2 * 10⁻⁴/2.00 * 10⁻⁵

v₁ = 10.0 mL of stock solution

Therefore, 10.0 ml of stock dye solution is required

c. Using m₁v₁ = m₂v

1.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁶

v₁ = 4 * 10⁻⁵/1.00 * 10⁻⁵

v₁ = 4.00 mL of stock solution

Therefore, 4.00 ml of stock dye solution is required

The procedure is then followed as in steps 2 to 4.

4 0
4 years ago
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