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Nezavi [6.7K]
3 years ago
6

How many grams of Fe can be produced when 6.50 g of Fe2O3 reacts?

Chemistry
1 answer:
AveGali [126]3 years ago
6 0

Answer:

Mass of Fe produced = 4.468 g

Explanation:

Given data:

Mass of Fe produced = ?

Mass of Fe₂O₃ react = 6.50 g

Solution:

Chemical equation:

2Fe₂O₃        →     4Fe + 3O₂

Number of moles of Fe₂O₃ ;

Number of moles = mass/molar mass

Number of moles = 6.50 g/159.69 g/mol

Number of moles = 0.04 mol

Now we will compare the moles of iron and ironoxide.

                    Fe₂O₃             :             Fe

                         2                :              4

                       0.04             :             4/2×0.04 = 0.08 mol

Mass of iron produced:

Mass = number of moles × molar mass

Mass = 0.08 mol × 55.85 g/mol

Mass = 4.468 g

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If 5.0 liters H2 (g) at STP is heated to a temperature of 985, pressure remaining constant, the new volume of the gas will be?
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Answer:

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General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
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Explanation:

<u>Step 1: Define</u>

Initial Volume: 5.0 L H₂ gas

Initial Temp: 273 K

Final Temp: 985 K

Final Volume: ?

<u>Step 2: Solve for new volume</u>

  1. Substitute:                    \frac{5 \ L \ H_2}{273 \ K} =\frac{x \ L \ H_2}{985 \ K}
  2. Cross-multiply:             (5 \ L \ H_2)(985 \ K) = (x \ L \ H_2)(273 \ K)
  3. Multiply:                        4925 \ L \ H_2 \cdot K = 273x \ L \ H_2 \cdot K
  4. Isolate <em>x</em>:                       18.0403 \ L \ H_2 = x
  5. Rewrite:                         x=18.0403 \ L \ H_2

<u>Step 3: Check</u>

<em>We are given 2 sig figs as the smallest. Follow sig fig rules and round.</em>

<em />18.0403 \ L \ H_2 \approx 18 \ L \ H_2<em />

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