Question

1. Perform calculations to determine the amount of 6.00x10-5 M stock solution needed to prepare 20.00 mL of 2.00x10-5 M dye solution. Perform calculations to determine the amount of 2.00x10-5 M stock solution needed to prepare 20.00 mL of 1.00x10-5 M dye solution. Perform calculations to determine the amount of 1.00x10-5 M stock solution needed to prepare 20.00 mL of 2.00x10-6 M dye solution. Show your calculations in your notebook. 2. Obtain approximately 10 mL of 6.00x10-5 M stock dye solution in a 50 mL beaker. The markings on the beaker are approximate measurements. 3. Prepare your 2.00x10-5 M solution using the 6.00x10-5 M stock dye solution. Measure the stock dye using a 25 mL graduated cylinder (feel free to use a glass pasteur pipette to measure the exact quantity you need). Add deionized water to the 20.00 mL mark on the graduated cylinder. Transfer the solution to a clean 50 mL beaker. 4. Using serial dilutions, prepare 20.00 mL of 1.00x10-5 M and 2.00x10-6 M solutions. Transfer the solutions to separate 50 mL beakers and arrange them on a labeled piece of paper.

Answer 1

Answer:

1a. 6.70 ml of stock dye solution is required

1b. 10.0 ml of stock dye solution is required

1c. 4.00 ml of stock dye solution is required

Explanation:

1a. Using m₁v₁ = m₂v

6.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁵

v₁ = 4 * 10⁻⁴/6.00 * 10⁻⁵

v₁ = 6.70 mL of stock solution

Therefore, 6.70 ml of stock dye solution is required

b. Using m₁v₁ = m₂v

2.00 * 10⁻⁵ * v₁ = 20.0 * 1.00 * 10⁻⁵

v₁ = 2 * 10⁻⁴/2.00 * 10⁻⁵

v₁ = 10.0 mL of stock solution

Therefore, 10.0 ml of stock dye solution is required

c. Using m₁v₁ = m₂v

1.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁶

v₁ = 4 * 10⁻⁵/1.00 * 10⁻⁵

v₁ = 4.00 mL of stock solution

Therefore, 4.00 ml of stock dye solution is required

The procedure is then followed as in steps 2 to 4.