Answer:
2.36 μ H
Explanation:
Given,
Number of turns= 90
diameter = 1.3 cm = 0.013 m
unscratched length = 57 cm = 0.57 m
Area, A = π r²
= π x 0.0065² = 1.32 x 10⁻⁴ m²
we know,
![L = \dfrac{\mu_0N^2A}{l}](https://tex.z-dn.net/?f=L%20%3D%20%5Cdfrac%7B%5Cmu_0N%5E2A%7D%7Bl%7D)
![L = \dfrac{4\pi \times 10^{-7}\times 90^2\times 1.32\times 10^{-4}}{0.57}](https://tex.z-dn.net/?f=L%20%3D%20%5Cdfrac%7B4%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%5Ctimes%2090%5E2%5Ctimes%201.32%5Ctimes%2010%5E%7B-4%7D%7D%7B0.57%7D)
L = 2.36 μ H
Hence, the inductance of the unstretched cord is equal to 2.36 μ H
Answer:
276.5 m/s^2
Explanation:
The initial angular velocity of the turbine is
![\omega=0.626 rev/s \cdot 2\pi rad/rev =3.93 rad/s](https://tex.z-dn.net/?f=%5Comega%3D0.626%20rev%2Fs%20%5Ccdot%202%5Cpi%20rad%2Frev%20%3D3.93%20rad%2Fs)
The length of the blade is
r = 17.9 m
So the centripetal acceleration is given by
![a=\omega^2 r](https://tex.z-dn.net/?f=a%3D%5Comega%5E2%20r)
At the instant t = 0,
![\omega=3.93 rad/s](https://tex.z-dn.net/?f=%5Comega%3D3.93%20rad%2Fs)
So the centripetal acceleration of the tip of the blades is
![a=(3.93 rad/s)^2 (17.9 m)=276.5 m/s^2](https://tex.z-dn.net/?f=a%3D%283.93%20rad%2Fs%29%5E2%20%2817.9%20m%29%3D276.5%20m%2Fs%5E2)
Answer:
Explanation:
When two forces acting on a line of action and they are equal in magnitude but opposite it direction, it forms a couple.
Torque is defined as the product of either force and the perpendicular distance between the two forces.
It is a vector quantity.
The net torque is zero, it means the anticlockwise torque is equal to the clockwise torque.
It means they balances each other.