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Lyrx [107]
3 years ago
11

Four students were loading boxes of food collected during a food drive. The force that each student exerted while lifting and th

e distance each box was lifted are listed in the table.
A 3-column table with 4 rows. The first column labeled student has entries Chet, Mika, Sara, Bill. The second column labeled Force (Newtons) has entries 50, 40, 30, 60. The third column labeled Distance (meters) has entries 1.0, 2.0, 1.5, 0.5.

Which lists the students in order from the greatest amount of work done to the least? (Work: W = Fd)
Physics
2 answers:
Aleonysh [2.5K]3 years ago
8 0

Answer:

The correct answer is B. Mika, Chet, Sara, Bill

Explanation:

Look at the picture

hope this helps :)

Fudgin [204]3 years ago
7 0

Answer:

it is B

Explanation:

Edge2020

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A merry-go-round is rotating at an angular speed of 0.2 radians/s. Its motor falls off and it rotates freely. A technician jumps
I am Lyosha [343]

Answer:

  I₁ =1250  kg.m²

Explanation:

Given that

Angular speed of Merry ,ω₁= 0.2 rad/s

Angular speed of technician ,ω₂= 0.04 rad/s

Moment of the inertia of the technician ,I₂= 5000 kg.m²

Lets assume that

Moment of the inertia of merry with respected to the ground=I₁

There is no any external torque ,that is why angular momentum of the system will be conserve.

Now by conserving angular momentum

I₁ ω₁=(I₁+I₂)ω₂

I₁  x 0.2  = (I₁ +5000 ) x 0.04

I₁ (0.2-0.04) = 5000 x 0.04

I_1=\dfrac{5000\times 0.04}{0.2-0.04}

I₁ =1250  kg.m²

5 0
3 years ago
If the coefficient of static friction between your coffee cup and the horizontal dashboard of your car is µs = 0.800, how fast c
Cloud [144]

Answer:

Before start of slide velocity will be 14.81 m/sec

Explanation:

We have given coefficient of static friction \mu =0.8

Angle of inclination is equal to \Theta =tan^{-1}\mu

\Theta =tan^{-1}0.8=38.65^{\circ}

tan{38.65^{\circ}}=0.8

Radius is given r = 28 m

Acceleration due to gravity g=9.8m/sec^2

We know that tan\Theta =\frac{v^2}{rg}

0.8=\frac{v^2}{28\times 9.8}

v^2=219.52

v=14.816m/sec

So before start of slide velocity will be 14.81 m/sec

3 0
3 years ago
chanice drives her scooter 7 km north she stops for lunch and then drives 5 km east what distance did she cover. what was her di
liberstina [14]
Use pythagorean's theorem for this, with 7 as a and 5 as b. pythagorean's theorem says that a^2 + b^2 = c^2, so 7^2 * 5^2 = c^2. this gives you 49 + 25 = c^2, so 74 = c^2. c = sqrt 74, which is approximately 8.60 km
3 0
3 years ago
If two clay masses produce a gravitational force of 340N, what will be the force if the distance is divided by 3 and the mass of
OverLord2011 [107]

Answer:

B: 1530 N

Explanation:

We know ghat formula for force of gravity is;

F_grav = G•m1•m2/d²

We are told that two clay masses produce a gravitational force of 340N.

Thus;

G•m1•m2/d² = 340

Now, if the distance is divided by 3 and the mass of one is divided by 2, we have;

F_g = (G × m1/2 × m2)/(d/3)²

Thus gives;

F_g = ½(G•m1•m2)/((1/9)d²)

Simplifying this gives;

F_g = (9/2)G•m1•m2/d²

From earlier, we saw that;

G•m1•m2/d² = 340

Thus;

F_g = (9/2) × 340

F_g = 1530 N

4 0
3 years ago
A 70-cm-diameter wheel accelerates uniformly from 160rpm to 280rpm in 4.0s. Determine (a) its angular acceleration, and (b) the
poizon [28]

Explanation:

Given that,

Diameter of the wheel, d = 70 cm = 0.7 m

Initial angular speed, \omega_i=160\ rpm=16.75\ rad/s

Final angular speed, \omega_f=280\ rpm=29.32\ rad/s

Time, t = 4 s

(a) Angular acceleration,

\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{29.32-16.75}{4}\\\\\alpha =3.14\ rad/s^2

(b) Tangential acceleration is :

a=r\alpha \\\\a=0.35\times 3.14\\\\a=1.085\ m/s^2  

Angular speed of the wheel after 2 seconds is :

\omega_f=\omega_i+\alpha t\\\\\omega_f=16.75+3.14\times 2\\\\\omega_f=23.03\ rad/s

Radial acceleration will be :

a=\omega_f^2r\\\\a=(23.03)^2\times 0.35\\\\a=185.6\ m/s^2

Hence, this is the required solution.

4 0
3 years ago
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