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nevsk [136]
3 years ago
5

What is the acceleration of the car at segment C?

Physics
2 answers:
eduard3 years ago
8 0
-30m/s2

Got it right on edge
nirvana33 [79]3 years ago
4 0

Answer:

-30 m/s2

Explanation:

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Vibrations that move through the ground carrying the energy released during an earthquake are called
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Answer is Seismic Wave
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Suppose you take a 50gram ice cube from the freezer at an initial temperature of -20°C. How much energy would it take to complet
notsponge [240]

Answer:

The amount of energy required is 152.68\times 10^{3}Joules

Explanation:

The energy required to convert the ice to steam is the sum of:

1) Energy required to raise the temperature of the ice from -20 to 0 degree Celsius.

2) Latent heat required to convert the ice into water.

3) Energy required to raise the temperature of water from 0 degrees to 100 degrees

4) Latent heat required to convert the water at 100 degrees to steam.

The amount of energy required in each process is as under

1) Q_1=mass\times S.heat_{ice}\times \Delta T\\\\Q_1=50\times 2.05\times 20=2050Joules

where

'S.heat_{ice}' is specific heat of ice =2.05J/^{o}C\cdot gm

2) Amount of heat required in phase 2 equals

Q_2=L.heat\times mass\\\\\therefore Q_{2}=334\times 50=16700Joules

3) The amount of heat required to raise the temperature of water from 0 to 100 degrees centigrade equals

Q_3=mass\times S.heat\times \Delta T\\\\Q_1=50\times 4.186\times 100=20930Joules

where

'S.heat_{water}' is specific heat of water=4.186J/^{o}C\cdot gm

4) Amount of heat required in phase 4 equals

Q_4=L.heat\times mass\\\\\therefore Q_{4}=2260\times 50=113000Joules\\\\\\\\\\\\Thus the total heat required equals Q=Q_{1}+Q_{2}+Q_{3}+Q_{4}\\\\Q=152.68\times 10^{3}Joules

5 0
3 years ago
1. What type of electromagnetic waves do cell phones use? <br><br>I WILL MARK AS BRAINLIEST
Yakvenalex [24]

Answer:

Radio waves

Explanation:

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3 years ago
Why does charging by rubbing happens best in dry weather?
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Maybe friction..? my best answer.
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You are riding in a hot air balloon that, relative to the ground, has a velocity of 6.0 m/s due east. You see a hawk moving dire
charle [14.2K]

Answer:Velocity = 6.325m/s

Directional angle= 18.43°

Explanation:

Using Right angle triangle

Let Velocity of ballon&hawk be VHB represent the height of the triangle.

Let Velocity of balloon angle ground be VBG represent adjacent of the triangle.

Let Velocity of hawk and ground BE VHG represent the hypothesis.

Theta = opp/Adj= VHB/VBG

using pythagorean

VHG= SQRT(VHB^2+VBG^2)

VHG= sqrt(2^2+6^2)

VHG= sqrt(4+36)

VHG= 6.325m/s

Tan theta= 2/6

Tan theta =0.3333

Tan^-1 0.3333=18.43°

8 0
3 years ago
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