Answer:
1.6875 m
Explanation:
Here, we are given that,
- Initial velocity (u) = 0 (as it starts from rest)
- Acceleration (a) = 1.5 m/s²
- Time taken (t) = 1.5 s
Then,
<u>By using the second equation of motion,</u>
★ s = ut + ½at²
- s is distance
- u is initial velocity
- t is time
- a is acceleration
⇒ s = 0(1.5) + ½ × 1.5 × (1.5)²
⇒ s = ½ × 1.5 × 2.25
⇒ s = ½ × 1.5 × 2.25
⇒ s = ½ × 3.375
⇒ s = 1.6875 m
∴ Distance travelled by it is 1.6875 m.
so for the first one it will be longitudinal wave then the second is transverse wave and the third is electromagnetic wave
Answer: 0.45
Explanation:
First note that the body that causes the body to move is its moving force (Fm) which is 9.0N
Since the mass of the body is 2.0kg, the weight will be;
W= mg = 2×10
W= 20N
For static body, the frictional force (Ff) acting on the body is equal to the moving force (Fm) since both forces acts along the horizontal on the body.
Ff = Fm = 9.0N
The normal reaction (R) on the body will also be equal to its weight(W) since weight acts downwards and the reaction acts in the opposite direction (upwards).
R = W = 20N
Ff = nR taking 'n' as coefficient of static friction between the drawer and the cabinet.
9.0 = 20n
n = 9/20
n = 0.45
The gravitational force <em>F</em> between two masses <em>M</em> and <em>m</em> a distance <em>r</em> apart is
<em>F</em> = <em>G M m</em> / <em>r</em> ²
Decrease the distance by a factor of 7 by replacing <em>r</em> with <em>r</em> / 7, and decrease both masses by a factor of 8 by replacing <em>M</em> and <em>m</em> with <em>M</em> / 8 and <em>m</em> / 8, respectively. Then the new force <em>F*</em> is
<em>F*</em> = <em>G </em>(<em>M</em> / 8) (<em>m</em> / 8) / (<em>r</em> / 7)²
<em>F*</em> = (1/64 × <em>G M m</em>) / (1/49 × <em>r</em> ²)
<em>F*</em> = 49/64 × <em>G M m</em> / <em>r</em> ²
In other words, the new force is scaled down by a factor of 49/64 ≈ 0.7656, so the new force has magnitude approx. 76.56 N.
Answer:
The sphere's volume charge density is 2.58 μC/m³.
Explanation:
Given that,
Radius of sphere R= 8.40 cm
Electric field
Distance r= 16.8 cm
We need to calculate the sphere's volume charge density
Using Gauss's law
Put the value into the formula
Hence, The sphere's volume charge density is 2.58 μC/m³.