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dedylja [7]
3 years ago
6

During a game of tug-of-war, one team exerts a force of 3,500 N to the left. The other team exerts a force of 3,800 N to the rig

ht. Which of the following statements is true about the game?
Select one:
a. The forces are balanced, and there will not be a winner.
b. The forces are unbalanced, and the second team will win.
c. The forces are balanced, and the first team will win.
d. The forces are unbalanced, and the first team will win.
Physics
2 answers:
NISA [10]3 years ago
8 0
B would be the correct answer.
Lunna [17]3 years ago
6 0
The answer is b hope this helps
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Is Natural Gas nonrenewable or renewable? Why? Use in your own words.
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Natural gas is non renewable energy.

Explanation:

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ASAP pls answer right if can’t see picture don’t answer
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Answer:

Not sure but

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An astronaut having mass 320 kg with equipment included is attempting an untethered space walk. The astronaut is initially at re
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7 0
3 years ago
A particle moves in a straight line with the velocity function v ( t ) = sin ( w t ) cos 3 ( w t ) . find its position function
Sunny_sXe [5.5K]

Integrating the velocity equation, we will see that the position equation is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

<h3>How to get the position equation of the particle?</h3>

Let the velocity of the particle is:

$v(t)=\sin (\omega t) * \cos ^2(\omega t)

To get the position equation we just need to integrate the above equation:

$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t

$\mathrm{u}=\cos (\omega \mathrm{t})

Then:

$d u=-\sin (\omega t) d t

\Rightarrow d t=-d u / \sin (\omega t)

Replacing that in our integral we get:

$\int \sin (\omega t) * \cos ^2(\omega t) d t$

$-\int \frac{\sin (\omega t) * u^2 d u}{\sin (\omega t)}-\int u^2 d t=-\frac{u^3}{3}+c$

Where C is a constant of integration.

Now we remember that $u=\cos (\omega t)$

Then we have:

$f(t)=\frac{\cos ^3(\omega t)}{3}+C

To find the value of C, we use the fact that f(0) = 0.

$f(t)=\frac{\cos ^3(\omega * 0)}{3}+C=\frac{1}{3}+C=0

C = -1 / 3

Then the position function is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

Integrating the velocity equation, we will see that the position equation is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

To learn more about motion equations, refer to:

brainly.com/question/19365526

#SPJ4

4 0
2 years ago
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