The area of sector AOB is . Find the exact area of the shaded region.

salantis [7]

I believe it's four times as great : )

4 0

3 years ago

A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. The

Delvig [45]

10 small boxes and 11 large boxes were shipped.

Step-by-step explanation:

Given,

Total boxes shipped = 21

Total volume of shipped boxes = 342 cubic feet

Volume of each small box = 10 cubic feet

Volume of each large box = 22 cubic feet

Let,

Number of small boxes = x

Number of large boxes = y

According to given statement;

x+y=21 Eqn 1

10x+22y=342 Eqn 2

Multiplying Eqn 1 by 10

$10(x+y=21)\\10x+10y=210\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(10x+22y)-(10x+10y)=342-210\\10x+22y-10x-10y=132\\12y=132$

Dividing both sides by 12

$\frac{12y}{12}=\frac{132}{12}\\y=11$

Putting y=11 in Eqn 1

$x+11=21\\x=21-11\\x=10$

10 small boxes and 11 large boxes were shipped.

Keywords: linear equation, subtraction

Learn more about linear equations at:

#LearnwithBrainly

3 0

3 years ago

The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle

AVprozaik [17]

Answer:

Length of rectangle is 31 yards and Width is 24 yards.

Given:

The length of a rectangle is 7 more than the width.
The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

$\\ \: \: \: \: \pink{ \dashrightarrow \: \: \: \: \sf { \underbrace{Area_{(Rectangle)} = Length × Width }}} \\ \\$

On Substituting the required values, we get;

$\\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x = 24 \: or \: - 31 \\ \\$