THE FIRST ANSWER is the answer
Answer: 0.8490
Step-by-step explanation:
Given : The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.0 inches and a standard deviation of 0.9 inches.
i.e.
and ![\sigma=0.9](https://tex.z-dn.net/?f=%5Csigma%3D0.9)
Let x denotes the lengths of aluminum-coated steel sheets.
Required Formula : ![z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
For n= 36 , the probability that the average length of a sheet is between 29.82 and 30.27 inches long will be :-
![P(29.82](https://tex.z-dn.net/?f=P%2829.82%3Cx%3C30.27%29%3DP%28%5Cdfrac%7B29.82-30%7D%7B%5Cdfrac%7B0.9%7D%7B%5Csqrt%7B36%7D%7D%7D%3C%5Cdfrac%7Bx-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%3C%5Cdfrac%7B30.27-30%7D%7B%5Cdfrac%7B0.9%7D%7B%5Csqrt%7B36%7D%7D%7D%29%5C%5C%5C%5C%3DP%28-1.2%3Cz%3C1.8%29%5C%5C%5C%5C%3DP%28z%3C1.8%29-P%28z%3C-1.2%29%5C%5C%5C%5C%3DP%28z%3C1.8%29-%281-P%28z%3C1.2%29%29%5C%20%5C%20%7B%5B%5Cbecause%5C%20P%28Z%3C-z%29%3D1-P%28Z%3Cz%29%5D%7D%5C%5C%5C%5C%3D%200.9641-%281-0.8849%29%5B%5Ctext%7BBy%20using%20z-table.%7D%5D%5C%5C%5C%5C%3D0.8490)
∴ Required probability = 0.8490
Answer:
Billy used 28 mins 30 sec to mow the lawn and Bobby used 43 mins 30 sec to now the lawn both within 72 mins
Step-by-step explanation:
let x represent Billy
let x+15 represent Bobby
x + x + 15 = 72
2x = 72 - 15
2x = 57
2x/2 = 57/2
x = 28.5 minutes = 28 minutes 30 seconds
Bobby = x + 15
= 28.5 + 15
= 43.5 minutes= 43 minutes 30 seconds
Answer:
First number = 60 and another number = 48
Step-by-step explanation:
Let two numbers are 5x and 4x.
The two number are differ by 12. We need to find the numbers.
ATQ,
5x-4x = 12
x = 12
Now first number = 5x
= 5(12)
= 60
Other number = 4x
= 4(12)
= 48
Hence, the numbers are 60 and 48.
Answer:
B.
Step-by-step explanation: