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VikaD [51]
3 years ago
8

Whats the exact area of a circle with a radius of 13 feet​

Mathematics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

530.93 or if you round to the nearest tenth its 530.9 or nearest whole number its 531

Step-by-step explanation:

Hope this Helps

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Solve his problem for X and Y​
Verizon [17]

<em><u>Answer:</u></em>

<em><u>y = 5, 3; x = 171, 155</u></em>

<em><u>Step-by-step explanation:</u></em>

8y - 15 = y^2

y^2-8y+15=0

y^2-3y-5y+15=0

y(y-3)-5(y-3)=0

(y-5)(y-3)=0

y can be 5 or 3.

x = 180 - (8y - 15)

x = 180 - (8(3)-15)

x = 180 - 9

x = 171

OR

x = 180 - (8(5) - 15)

x = 180 - 25

x = 155

7 0
3 years ago
un automovil marcha durante 3/8 del dia a una velocidad constante de 16 km/h ¿cual es el espacio recorrido?.......Doy corona al
Tanzania [10]

Answer:

LOL

Step-by-step explanation:

144 KILOMETROS....

5 0
2 years ago
Determine the open t-intervals on which the curve is concave downward or concave upward. (Enter your answer using interval notat
Rashid [163]

Solution :

We have been given a parametric curve :

x = sin t , y = cos t , 0 < t < π

In order to determine concavity of the given parametric curve, we need to evaluate its second derivative first.

Therefore,

$\frac{dx}{dt} = \cos t, \ \frac{dy}{dt}= - \sin t$

$\therefore \frac{dy}{dx}= \frac{- \sin t}{\cos t}$

        $=- \tan t$

Taking double derivatives of the above equation:

$\frac{d^2y}{dx^2}= - \frac{d}{dx}(\tan t) $

      $= - \sec^2 t \frac{dt}{dx}$

     $= - \sec^2 t \left(\frac{1}{\cos t}\right)$

    $= - \sec^3 t$

For the concave up, we have

$\frac{d^2y}{dx^2} > 0$

$\Rightarrow - \sec^3 t > 0$

∴ $t \  \epsilon \left( \frac{\pi }{2}, \pi \right)$

For the concave down, we have

$\frac{d^2y}{dx^2} < 0$

$\Rightarrow - \sec^3 t < 0$

$t \  \epsilon \left( 0,\frac{\pi }{2} \right)$

8 0
3 years ago
What is the solution for the system of equations?
Lena [83]

Answer:

1, 3

Step-by-step explanation:

// Solve equation [2] for the variable  y  

  [2]    y = x - 2

// Plug this in for variable  y  in equation [1]

[1]    (x -2) + x = 4

  [1]    2x = 6

// Solve equation [1] for the variable  x  

[1]    2x = 6  

[1]    x = 3  

// By now we know this much :

y = x-2

x = 3

// Use the  x  value to solve for  y  

 y = (3)-2 = 1

5 0
3 years ago
Your team lost by 13 points. The opposing team scores 72 points. What was your final score?
DanielleElmas [232]
The final score is 59
4 0
3 years ago
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