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3 years ago

What is 2+6*5/8 ? I need help with this math problem , thank you.

Mathematics

2 answers:

vampirchik [111]3 years ago

8 0

Hey.

I hope that you're familiar with P.E.M.D.A.S :)

applying PEMDAS :

2 + 6 × 5 ÷ 8

2 + 30 ÷ 8

32 ÷ 8 = 4

Hence, The required answer is 4

Thanks.

PSYCHO15rus [73]3 years ago

8 0

Answer:

Step-by-step explanation:

2 + 6 · 5 ÷ 8 = ?

We will do PEMDAS

2 + 6 = 8

2 + 30 ÷ 8

32 ÷ 8 = 4

Hope this helps!

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Correct answer get the BRAINLIEST ANSWER!

OLga [1]

Here is how I completed the problem:

I started by creating a ratio:

$\frac{x}{0.18} + \frac{360}{0.10} = \frac{x+360}{0.15}$

<em>Where 'x' is the desired amount of the 18% solution of sulfuric acid.

</em>From here, I solved for 'x':
<em>
</em> $\frac{0.10x}{0.018} + \frac{360(0.18)}{0.018} = \frac{x+360}{0.15}$
$\frac{0.10x}{0.018} + \frac{64.8}{0.018} = \frac{x+360}{0.15}$
$\frac{0.10x+64.8}{0.018} = \frac{x+360}{0.15}$
$0.15(0.10x+64.8) = 0.018(x+360)$
$0.015x+9.72 = 0.018x+6.48$
$0.003x = 3.24$
$x = 1080$

∴You will need to add 1080ml of 18% Sulfuric Acid in order to obtain a 15% solution.

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3 years ago

Three roots of a polynomial equation with real coefficients are 3, 5 – 3i, and −3i. Which of the following numbers must also be

Leviafan [203]

Answer is D (−3, 5 + 3i, and 3i)

4 0

3 years ago

(26)(1230)=24x how do I solve this

ira [324]

Answer:

x=1332.5

Step-by-step explanation:

24x=(26)(1230)

24x=31980

divide both sides by 24

x=1332.5

7 0

3 years ago

Read 2 more answers

PLEASE HELPP I WILL MARK YOU GOOD

djverab [1.8K]

Answer:

Volume: 41.643

Surface area: 119.04 (nearest tenth... I don't know...sorry)

Step-by-step explanation:

I didn't know if you need volume or surface area so you got both!

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3 years ago

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

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3 years ago