Division yields

Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that


which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

Now, in the integral we get

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get

I honestly don’t know but I hope you find the answer to this question soon and have a good night good luck
Solve the "f" function with substitute 4 and solve the "g" function with what we get for the "f" function.
f(4) = 2(8) + 3
f(4) = 16 + 3
f(4) = 19
g(19) = 4(19) - 1
g(19) = 76 - 1
g(19) = 75
Best of Luck!
Answer: the answer to (g+h)x4 is
4g+4h
Step-by-step explanation:
(g+h)x4
multiply the parentheses by 4
and that will give you 4g+4h
sorry if it was wrong