Use subtitution method to solve the problem.
First, change y to the value of x in order to find the exact value of x.
x + y = 4
y = 4 - x
Second, subtitute y with 4 - x from the first equation
y = -x² + 2x + 4
4 - x = -x² + 2x + 4
move all terms to the left side
x² - 2x - x + 4 - 4 = 0
x² - 3x = 0
x(x - 3) = 0
x = 0 or x = 3
Third, now we have 2 values of x. Find the value of y for each of x
For x = 0
y = 4 - x
y = 4 - 0
y = 4
For x = 3
y = 4 - x
y = 4 - 3
y = 1
The solution is (0,4) and (3,1). The answer is option b
41, 50, 59
all you have to do is subtract the first number from the second number which is 9. then you add 9 to the last number to get your answer
The number of tops on the 6th day based on the exponential model is 64, and the number of tops on the 6th day based on the linear model is 17.
<h3>What is an exponential function?</h3>
It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent 
where a is a constant and a>1
First day class collected = 2 tops
Third day class collected = 8 tops
The exponential function can be modelled:

D(1) = 2 (first day)
D(3) = 8 (third day)
D(6) = 64 (sixth day)
The linear function can be modeled:
D(N) = 3N -1
D(1) = 2 (first day)
D(3) = 8 (third day)
D(6) = 17 (sixth day)
Thus, the number of tops on 6th day based on exponential model is 64, and the number of tops on the 6th day based on the linear model is 17.
Learn more about the exponential function here:
brainly.com/question/11487261
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The first equation has a solution of X=-5
Answer:
DB = CA (Proved)
Step-by-step explanation:
Statement 1.
∠D = ∠C, M is the midpoint of DC and ∠1 = ∠2
Reason 1.
Given
Statement 2.
Between Δ DBM and Δ CAM,
(i) DM = CM,
(ii) ∠D = ∠C and
(iii) ∠DMB = ∠CMA
Reason 2.
(i) given
(ii) given and
(iii) ∠ DMB = ∠1 + ∠AMB and ∠CMA = ∠2 + ∠AMB
Since ∠1 = ∠2, so, ∠DMB = ∠CMA.
Statement 3.
Δ DBM ≅ Δ CAM
Reason 3.
By angle-side-angle rule.
Statement 4.
DB = CA
Reason 4.
Corresponding sides of two congruent triangles. (Answer)