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Ivahew [28]
3 years ago
10

You have $75.00 to spend at the mall. You want to buy a hoodie that costs $80.00. The store is having a 20%-off sale. (There is

no tax on clothing.) Can you buy the hoodie? If so, how much money will you have left?
Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0
$80.00 x 0.20 = $16.00
$80.00 - 16.00 = $64.00
the hoodie costed $64.00
you were left with $16 to spare

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Marina86 [1]
I think it might be 50? unless you meant 2/100, which is 0.02
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in abbys grade, there 70 students. currently, 10% of them are enrolled in health. how many students are enrolled in health?​
goblinko [34]

Answer:

7 students.

Step-by-step explanation:

10% of 70 is 7.

4 0
2 years ago
*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts
Nataly [62]

Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

The horizontal asymptote is y=2.

The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

0=\frac{2x+1}{x-3}

A fraction is only 0 when it's numerator is 0.  You are really just solving:

0=2x+1

Subtract 1 on both sides:

-1=2x

Divide both sides by 2:

\frac{-1}{2}=x

The x-intercept is (\frac{-1}{2},0).

The y-intercept is when x is 0.

Replace x with 0.

g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

y=\frac{0+1}{-3}

y=\frac{1}{-3}

y=-\frac{1}{3}.

The y-intercept is (0,\frac{-1}{3}).

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0
3 years ago
Find the volume of a cone with a base diameter of 6yd and a height of 10yd .
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About 94.24778. The radius is 3.
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Read 2 more answers
When your class visited the aquarium, the costs totaled the maximum
yanalaym [24]

Answer:

I think it's A

Step-by-step explanation:

Please correct me if I'm wrong

7 0
3 years ago
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