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KengaRu [80]
3 years ago
8

Nancy decides to roll a dice three times. What is the probability that she will roll all even numbers?

Mathematics
1 answer:
inessss [21]3 years ago
3 0

Given:

Nancy decides to roll a dice three times.

To find:

The probability that she will roll all even numbers.

Solution:

If a dice is rolled, then the possible numbers are

Total number = {1,2,3,4,5,6} = 6

Even numbers = {2,4,6} = 3

Odd numbers = {1,3,5} = 3

Probability of getting an even number =\dfrac{\text{Even number}}{\text{Total numbers}}

P(\text{Even})=\dfrac{3}{6}

P(\text{Even})=\dfrac{1}{2}

So, probability of getting all even numbers is

P(\text{All even})=P(\text{Even})\times P(\text{Even})\times P(\text{Even})

P(\text{All even})=\dfrac{1}{2}\times \dfrac{1}{2}\times \dfrac{1}{2}

P(\text{All even})=\dfrac{1}{8}

Therefore, the required probability is P(\text{All even})=\dfrac{1}{8}.

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Answer:

n=22 or 252=11(22)+10

Step-by-step explanation: 252=11n+10. Start by attempting to isolate the varyable by subracting 10 from both sides--> 242=11n, divide by 11--> 22=n

PROOF 252=11*22+10=242+10=252


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Given:

Consider the pentagon MVEDR is dilated with the origin as the center of dilation using the rule (x,y)\to(\dfrac{2}{3}x,\dfrac{2}{3}y) to create pentagon M'V'E'D'R'.

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The correct statement.

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