Ask question

Ask question

All categories

brilliants [131]

3 years ago

6

Evaluate the expression when x = 2

1 answer:

Andrews [41]3 years ago

3 0

The answer is 1 when x=2

You might be interested in

Cot^2 135-sin210+5cos^2 225

TiliK225 [7]

$\cot135^o=\cot(90^o+45^o)=-\tg45^o=-1\\\\\sin210^o=\sin(180^o+30^o)=-\sin30^o=-\dfrac{1}{2}\\\\\cos225^o=\cos(180^o+45^o)=-\cos45^o=-\dfrac{\sqrt2}{2}$

$\cot^2135^o-\sin210^o+5\cos^2225^o=(-1)^2-\left(-\dfrac{1}{2}\right)+5\cdot\left(-\dfrac{\sqrt2}{2}\right)^2\\\\=1+\dfrac{1}{2}+5\cdot\dfrac{1}{2}=1\dfrac{1}{2}+2\dfrac{1}{2}=4$

Answer: 4.

3 0

4 years ago

Helppp meeeeeee asappppppp

Juliette [100K]

Answer:

9.2

Step-by-step explanation:

So the 14 can be divided equally on both sides by the fact that the line cutting it at right angle bisects it.

Thus having 6 and 7 as the two shorter sides of a right angled triangle will help us get the radius( hypotenuse in this case) using the square root of the sum of the squares of both six and 7, the Pythagoras theory.

this leads to 9.2 as our answer

5 0

3 years ago

Whats 811 divide by 25

NARA [144]

Answer:

the answer would be 32.44

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Olenka [21]

Answer:

a

The 90% confidence interval that estimate the true proportion of students who receive financial aid is

$0.533 < p < 0.64$

b

$n = 1789$

Step-by-step explanation:

Considering question a

From the question we are told that

The sample size is n = 200

The number of student that receives financial aid is $k = 118$

Generally the sample proportion is

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{118}{200}$

=> $\^ p = 0.59$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }$

=> $E = 0.057$

Generally 90% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.533 < p < 0.64$

Considering question b

From the question we are told that

The margin of error is E = 0.03

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the sample size is mathematically represented as

$[\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )$

=> $n = 1789$

8 0

3 years ago

John bought a computer scanner and supplies for $215.70, which will

lutik1710 [3]

Answer:

John must scan at least 863 images before he pays less on his own rather than in the store

Please vote for Brainliest and I hope this helps!

8 0

2 years ago