Answer :
556.59 m/s.
Explanation:
Given that,
An airplane is traveling at an altitude of 15,490 meters.
A box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.
The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :
Put u = 0 and a = g
So, when it hits the ground its velocity is 556.59 m/s.
Complete Question:
The momentum of an object is determined to be 7.2 × 10-3 kg⋅m/s. Express this quantity as provided or use any equivalent unit. (Note: 1 kg = 1000 g).
Answer:
7.2 gm/s.
Explanation:
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
Given the following data;
Momentum = 7.2 * 10^-3 kgm/s
1 kg = 1000 g
Substituting the unit in kilograms with grams, we have;
Momentum = 7.2 * 10^-3 * 1000 gm/s
<em>Momentum = 7.2 gm/s. </em>
Answer:
Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.
Explanation:
The distance from the central band to the first bright band is given by
where is the wavelength of light (or any particle),
is the distance to the screen, and
is the slit separation.
From this equation we see that, by increasing the wavelength , increasing the distance from the screen
, and decreasing the slit separation
, we increase the distance between the first bright band and the central band.
Therefore, the 2nd choice "<em>Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.</em>" is correct.