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poizon [28]
3 years ago
12

An airplane is traveling at an altitude of 15,490 meters. A box of supplies is dropped from its cargo hold. What is the cargo's

velocity when it hits the ground? (Show your work and do not forget units)
Physics
1 answer:
topjm [15]3 years ago
8 0

Answer :

556.59 m/s.

Explanation:

Given that,

An airplane is traveling at an altitude of 15,490 meters.

A  box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.

The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :

v^2-u^2=2as

Put u = 0 and a = g

v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s

So, when it hits the ground its velocity is 556.59 m/s.

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A ball is tossed up into the air, reaches its highest point and returns to its original position. which of the following is true
Gekata [30.6K]

Answer: (Projectile motion)

Option A — At its highest point the ball’s velocity is 0 and so it it’s acceleration (0).

This is because at the highest point, the ball’s direction changes. This is due to the forces counteracting the upward momentum (mass*velocity) of the ball, so the ball slows down and when it reaches it highest point starts to change direction and fall back down. In the short period of time at which its at its highest point, it’s velocity reaches 0 for a very short amount of time, and so does its acceleration.

3 0
3 years ago
A child is given an initial push on a rope swing. On the first​ swing, the rope swings through an arc of 12 feet. On each succes
marin [14]

Answer:

After 14 swings, total length = 57.35 feet.

When the child stops swinging, Total length = 60 feet.

Explanation:

The total length of the rope after 14 swings form a geometric progression which is also known as exponential sequence.

The sum of the term in a Geometry progression is

Sₙ = a(1-rⁿ)/1-r.................(1)

Where Sₙ = sum of the nth term, a= first term, n= number of term, r= common ratio.

n=14, a= 12 feet, r=80% = 0.8.

Substituting the values above into equation(1)

S₁₄ = 12(1-0.8¹⁴)/1-0.8

S₁₄=  12(1-0.04398)/1-0.8

S₁₄=   12(0.95602)/0.2

S₁₄ = 11.47/0.2

S₁₄= 57.35 feet

∴ After 14 swings, the total length the rope will swing is = 57.35 feet.

The total length of the rope  when the child stop swinging = sum to infinity of the Geometry progression( exponential sequence).

The sum to infinity of an exponential sequence

S = a/1-r

Where a= first term= 12 feet, r= common ratio = 0.8.

∴ S= 12/1-0.8

  S= 12/0.2

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When the boy stops swinging, the total length the rope have swung = 60 feet.

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== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = <em>1/4 as much</em> kinetic energy.

== A 50 kg <u>person</u> falling at 10 m/s would have <em>exactly the same</em> amount of kinetic energy as the 50 kg <u>ball</u> traveling at 10 m/s.

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