Answer:
50°
Explanation:
Projectiles launched at complementary angles have the same range.
<span>So, average angular velocity = angle/time = 90/1.5 = 60deg/second = (pi/3 radians/second) </span>
Answer:
38.35 bar
Explanation:
We are given that
Temperature=T=36.6 degree Celsius=36.6+273=309.6 K
Given mass of glucose=9.18 g
Molar mass of glucose(
=180 g
Mass of c=12 g,mass of hydrogen=1 g, mass of O=16 g
Volume of solution=34.2 mL
Molarity of solution=![\frac{given\;mass}{molar\;mass\times volume}\times 1000](https://tex.z-dn.net/?f=%5Cfrac%7Bgiven%5C%3Bmass%7D%7Bmolar%5C%3Bmass%5Ctimes%20volume%7D%5Ctimes%201000)
Where volume (in mL)
Molarity of solution=![\frac{9.18}{180\times 34.2}\times 1000=1.49 M](https://tex.z-dn.net/?f=%5Cfrac%7B9.18%7D%7B180%5Ctimes%2034.2%7D%5Ctimes%201000%3D1.49%20M)
We know that
Osmotic pressure=![\pi=MRT](https://tex.z-dn.net/?f=%5Cpi%3DMRT)
Where M=Molarity of solution
R=Constant=0.08314 Lbar/mol k
T=Temperature in kelvin
Using the formula
![\pi=1.49\times 0.08314\times 309.6=38.35 bar](https://tex.z-dn.net/?f=%5Cpi%3D1.49%5Ctimes%200.08314%5Ctimes%20309.6%3D38.35%20bar)
Hence, the osmotic pressure=38.35 bar
The water would be because however much salt you add the water rises