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bonufazy [111]
3 years ago
11

What is the acceleration of a ball that has dropped from a six-story building​

Physics
1 answer:
a_sh-v [17]3 years ago
7 0

Answer:

Because the ball is dropped, we are going to assume its initial velocity is 0. With that said, acceleration is essentially the change in the velocity versus the change in time, hence the unit m/s^2, which can be thought of as “meters per second per second.” The only force acting on the ball is gravity.

That being said, you can simply divide the change in velocity by the change in time, giving you an answer of 9.8 m/s^2, which is the value of g. Even if they did not give you a time, the answer would still always be the value of g (that is if the question pertains to earth), as acceleration due to gravity is a constant.

Explanation:

Please mark brainliest

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Explanation:

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pochemuha

Answer:

  • Disk C and Disk D

Explanation:

The total charge in the disks

q_1 + q_2 = q_{total}

must be conserved before and after bringing them together.

Lets equate the sum of the initial charge with the sum of the final for the disk:

q_{1_i} + q_{2_i} = q_{1_f} + q_{2_f} = 2 * (+8.5) \mu C

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So, the initial charges must sum +17 μC.

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3 0
3 years ago
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Ghella [55]

Answer:

0.765m

Explanation:

gravitational potential energy GPE = mass * acceleration due to gravity * height

Given

GPE = 30Joules

Mass m = 4kg

acceleration = 9.8m/s²

Required

Height h

From the formula

h = GPE/mg

h = 30/4(9.8)

h = 30/39.2

h = 0.765m\

Hence the height of the counter is 0.765m

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