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fiasKO [112]
3 years ago
6

If f(x) = 3x + 2, what is f(5)?

Mathematics
2 answers:
AleksandrR [38]3 years ago
6 0

Answer:

The correct answer is B. 17

Step-by-step explanation:

Andrei [34K]3 years ago
5 0

Answer:

f(5) = 17

Step-by-step explanation:

You just plug in 5 for x:

f(5) = 3(5) + 2

f(5) = 15 +2

f(5) = 17

Hope this helps!

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While eating a big bowl of pho (Vietnamese soup), you discover that the diameter of the bowl is 9 inches. What is the circumfere
Sever21 [200]
Circumference = π × diameter
π × 9 = 28.274333882
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7 0
3 years ago
A metalworker has a metal alloy that is 15​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
coldgirl [10]

18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

<u>Step-by-step explanation:</u>

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

51% of 90 kg = 45.9 kg of copper

So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

but

x + y = 90

x= 90 - y

substituting that value in for x

0.15(90 - y) + 0.60y = 45.9

13.5 - 0.15y + 0.60y = 45.9

0.45y = 32.4

y = 72

Substituting this y value to solve for x gives:

x + y = 90

x= 90-72

x=18

Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.

6 0
3 years ago
What degree of rotation about the origin will cause the triangle below to map
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Two payment options to rent a car: You can pay $20 a day plus 25¢ a mile (Option A) or pay $10 a day plus 50¢ a mile (Option B).
BaLLatris [955]

You must drive more than 40 miles to make option A the cheaper plan

<em><u>Solution:</u></em>

Two payment options to rent a car

Let "x" be the number of miles driven in one day

<em><u>You can pay $20 a day plus 25¢ a mile (Option A)</u></em>

25 cents is equal to 0.25 dollars

OPTION A :  20 + 0.25x

<em><u>You pay $10 a day plus 50¢ a mile (Option B)</u></em>

50 cents equal to 0.50 dollars

Option B: 10 + 0.50x

<em><u>For what amount of daily miles will option A be the cheaper plan ?</u></em>

For option A to be cheaper, Option A must be less than option B

Option A < Option B

20 + 0.25x < 10 + 0.50x

Solve the inequality

Add -0.50x on both sides

20 +0.25x -0.50x < 10 + 0.50x - 0.50x\\\\20 - 0.25x < 10

Add - 20 on both sides,

20 - 0.25x - 20 < 10 - 20\\\\-0.25x < -10

\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}

0.25x > 10

Divide both sides by 0.25

x > 40

Thus you must drive more than 40 miles to make option A the cheaper plan

7 0
3 years ago
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