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3 years ago

Shirt cost $20 each and ties cost $12 each. Write an expression for the cost of s shirts and t ties

Mathematics

2 answers:

gtnhenbr [62]3 years ago

8 0

Answer:

The cost of "s" shirts and "t" ties = $20s + $12t

Step-by-step explanation:

Given:

Shirt cost = $20 each

Ties cost = $12 each.

The number of shirts represented by "s" and the number of ties represented by "t"

Cost = $20*the number of shirts + $12*the number of ties

so, the cost of "s" shirts and "t" ties = 20s + 12t

Example:

If we want to find the cost 2 shirts and 3 ties, we need to plug s = 2 and t= 2 in the above expression.

The cost of 2 shirts and 3 ties = 20*2 + 12*3

= 40 + 36

= $76

The cost of 2 shirts and 3 ties is $76.

Ierofanga [76]3 years ago

6 0

20s+12t= is your expression.

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Read 2 more answers

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5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.

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The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

#initialize a function named gcd which takes in two parameters

if a>b:

#checks if a is greater than b

return gcd (b, a)

#if true interchange the Parameters and Recall the function

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

#even numbers leave no remainder when divided by 2, checks if a and b are even

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

#checks if a is odd and B is even

return gcd(a, b/2)

else :

return gcd(a, b-a)

#since it's a recursive function, it recalls the function with new parameters until a certain condition is satisfied

print(gcd(124, 244))

print()

#leaves a space after the first output

print(gcd(4424, 2111))

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