Answer:
Step-by-step explanation:
2/
5
k−
3
/5
k+
1
/10
k
=
2
/5
k+
−3
/5
k+
1
/10
k
Combine Like Terms:
=
2
/5
k+
−3
/5
k+
1
/10
k
=(
2
/5
k+
−3
/5
k+
1
/10
k)
=
−1
/10
k
Answer:
=
−1
/10
k
Answer:
<h2>You've worked with numbers on a number line. You know how to graph numbers like 0, 1, 2, 3, etc. on the number line. There are other kinds of numbers that can be graphed on the number line, too. Let's see what they look like and where they are located on the number line.</h2>
Step-by-step explanation:
<h2>Hope this helps!!</h2>
y = - 
x - 34
the equation of a line in slope-intercept form is
y = mx + c ( m is the slope and c the y-intercept )
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 68, 0 ) and (x₂, y₂ ) = (0, - 34 )
m = 
= 
= -
the y-intercept = (0, - 34 ) ⇒ c = - 34
y= - x - 34
Y = 9x - 5...the slope here is 9...a parallel line will have the same slope.
y = mx + b
slope(m) = 9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = 9(5) + b
-4 = 45 + b
-4 - 45 = b
-49 = b
so ur parallel line is : y = 9x - 49
y = 9x - 5...slope is 9. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/9.
y = mx + b
slope(m) = -1/9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = -1/9(5) + b
-4 = -5/9 + b
-4 + 5/9 = b
-36/9 + 5/9 = b
- 31/9 = b
so ur perpendicular line is : y = -1/9x - 31/9
