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Darya [45]
3 years ago
11

Multiply and simplify: y(2x+3y)(2x+3y)

Mathematics
2 answers:
vekshin13 years ago
6 0
<span>Simplifying y(2x + 3y)(2x + 3y)

Multiply (2x + 3y) * (2x + 3y) y(2x * (2x + 3y) + 3y * (2x + 3y)) y((2x * 2x + 3y * 2x) + 3y * (2x + 3y))
 
Reorder the terms: y((6xy + 4x2) + 3y * (2x + 3y)) y((6xy + 4x2) + 3y * (2x + 3y)) y(6xy + 4x2 + (2x * 3y + 3y * 3y)) y(6xy + 4x2 + (6xy + 9y2))

Reorder the terms: y(6xy + 6xy + 4x2 + 9y2)
 
Combine like terms: 6xy + 6xy = 12xy y(12xy + 4x2 + 9y2) (12xy * y + 4x2 * y + 9y2 * y) (12xy2 + 4x2y + 9y3)</span>
sladkih [1.3K]3 years ago
3 0
2xy+3y^2*2xy+3y^2
3y^2 * 3y^2
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Circle has a radius of 6 cm.
coldgirl [10]

Answer:

  • d=2r
  • d=2×6
  • d=12
  • circumference =2×pie×r
  • =2×22/7×6
  • 37.71
  • SO 37 is the ans
3 0
2 years ago
In circle A below, chord BC and diameter DAE intersect at F. If arc CD = 46° and arc BE = 78°, what is m_BFE? D B А​
wel

Given:

Consider the below figure attached with this question.

In circle A below, chord BC and diameter DAE intersect at F.

The arc CD = 46° and arc BE = 78°.

To find:

The measure of angle BFE.

Solution:

According to intersecting chords theorem, if two chords intersect inside the circle then the angle on the intersection is the average of intercepted arcs.

Using intersecting chords theorem, we get

m\angle BFE=\dfrac{1}{2}(m(arcCD)+m(arcBE))

m\angle BFE=\dfrac{1}{2}(46^\circ+78^\circ)

m\angle BFE=\dfrac{1}{2}(124^\circ)

m\angle BFE=62^\circ

Therefore, the measure of angle BFE is 62°.

6 0
3 years ago
The perimeter of a kite can be found using the formula P = 2S + 2L. Which equation expresses S in terms of P and L?
zimovet [89]

Answer:

<h2>The answer is A</h2><h2>A. S = 1/2p - L</h2>

Step-by-step explanation:

Step one:

given the perimeter function

P = 2S + 2L

we are expected in this problem to change the subject of the formula to S

Step two:

firstly, let us isolate the term that has S

2S=P-2L

divide both sides by 2

2S/2= (P-2L)/2

S=P/2-L

S = 1/2p - L

5 0
2 years ago
Demi’s last 5 bowling scores were 68, 75, 90, 80. What was Femi’s mean score? A.72 B.75 C.77 D.79 D.
-Dominant- [34]

Complete Question:

Femi's last 5 bowling scores were 68, 75, 72, 90, and 80.  What was Femi's mean score?

Answer:

Step-by-step explanation:

Given

Scores: 68, 75, 72, 90, and 80

Required

Determine the mean

The mean (M) of a data is calculated as thus:

M = \frac{\sum x}{n}

Where

n = number of data.

In this case,

n = 5

and

\sum x = sum of data

So, the formula becomes

M = \frac{68 + 75 + 72 + 90 + 80}{5}

M = \frac{385}{5}

M = 77

<em>Hence, the mean is 77</em>

5 0
2 years ago
On a coordinate plane, 2 triangles are shown. The first triangle has points M (negative 5, 4), N (negative 2, 3), and L (negativ
worty [1.4K]

Answer:

The rule of the reflection is rx-axis(x, y) → (x, –y) ⇒ 3rd answer

Step-by-step explanation:

Let us revise the reflection on the axes

If point (x , y) reflected across the x-axis , then its image is (x , -y) , the rule of reflection is rx-axis (x , y) → (x , -y)

If point (x , y) reflected across the y-axis , then its image is (-x , y) , the rule of reflection is ry-axis (x , y) → (-x , y)

In Δ LMN

∵ L = (-4 , 2)

∵ M = (-5 , 4)

∵ N = (-2 , 3)

In ΔL'M'N'

∵ L' = (-4 , -2)

∵ M' = (-5 , -4)

∵ N' = (-2 , -3)

The signs of y-coordinates of the vertices of Δ LMN are changed, that means Δ LMN are reflected across the x-axis

∵ The y-coordinate of L is 2 and the y-coordinate of L' is -2

∵ The y-coordinate of M is 4 and the y-coordinate of M' is -4

∵ The y-coordinate of N is 3 and the y-coordinate of N' is -3

∴ Δ LMN is reflected across the x-axis

∴ The image of point (x , y) is (x , -y)

The rule of the reflection is rx-axis(x, y) → (x, –y)

7 1
3 years ago
Read 2 more answers
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