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3 years ago

What is the slope of the line in the graph?

Mathematics

1 answer:

ch4aika [34]3 years ago

5 0

Answer:

2/4

Step-by-step explanation:

pick two points from the graph

rise / run

goes up 2 goes right 4 .

therefore

2/4

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Log base 9 m - log base 9 (m-4)=-2

choli [55]

Hello,

log base 9(m/(m-4))=-2
==>m/(m-4)=9^(-2)
==>81m=m-4
==>80m=-4
==>m=-1/20

4 0

3 years ago

Some one plz help meh I need to understand and I dont

vfiekz [6]

Answer:

It's asking you to find the inputs of the function.

Step-by-step explanation:

Basically, when you input something, you replace "x" in the equation with the number you want to input. For example, if I had the equation: 5x/6+5, then I wanted to input "5", then 5 would replace x in the equation, making 5(5)/6+5. The output they are giving you is simply evaluating the equation that you used to input x, so basically in the case I gave you, the output would be 5(5)/6+5, or 25/6+5, and 55/6. Using the outputs, they want you to find the inputs.

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3 years ago

Is -77 a rational or irrational number?

Butoxors [25]

It’s a rational number.

Hope this helps!

7 0

3 years ago

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Emily purchased three different sizes of popcorn at the movies. The medium popcorn was twice as expensive as the small popcorn.

MaRussiya [10]

Answer:

Step-by-step explanation:

medium popcorn- 2x

total - $23

large- 2x+3

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6 0

3 years ago

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Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

3 years ago

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