Let the first brother = x
second brother = x + 2
third brother = x + 4
<span>The product of the first and third boys' ages is 20 more than twice the second boy's age:
x(x+4) = 2(x+2) + 20
x</span>² + 4x = 2x + 4 + 20
x² + 4x - 2x - 24 = 0
x² + 2x - 24 = 0
(x - 4)(x + 6) = 0
x = 4 or -6 (rejected, age cannot be negative)
First brother = 4
Second brother = 4 + 2 = 6
Third brother = 4 + 4 = 8
The three boys are 4, 6, and 8 years old.
C and D tell me if those are wrong because i'm only a beginner and i would like to learn from my mistakes
Answer:
No real solution- Not any of the options anyway
Step-by-step explanation:
So I replaced the x's with the two possible equations and then tried to solve...
2=4+(4x2-4)1/2
2=4+(8-4)1/2
2=4+(4)1/2
2=8(1/2)
2=4 Which is not true
10=4+(4x10-4)1/2
10=4+(40-4)1/2
10=4+36(1/2)
10=40(1/2)
10=20 Which is also not true
Therefore, there is no real solution
You didn’t put the picture of your problem
Answer:
d (2)
Step-by-step explanation:
your moving forward two spaces
