Use A Calculator. They are Good Espically those chocolated smelled ones. :)
Fourteen go to wolfram and it will show you the details
For a 7*7=49 so sqrt(49)=7
6*6=36 so sqrt(36)=6
and since sqrt(x) is am increasing function then
6 < sqrt(42) <7
you do the same for b but with 4 values :
like 4*4*4= 64
and 3*3*3=27
Answer:
P_1st year = P0 x (1 + r/n) = P0 x (1 + r/n)^1
P_2nd year = P0 x (1 + r/n) (1 + r/n) = P0 x (1 + r/n)^2
...
P_n year = P0 x (1 + r/n)^n
Hope this helps!
:)
By using the definition of <em>second order</em> polynomials and the discriminant from <em>quadratic</em> formula, we conclude that the values of k must be less than 1/4.
<h3>How to determine the value of k such that a line intersects a quadratic equation</h3>
In this question we must determine the set of values of k such that the function g(x), a <em>linear</em> function, intersects a<em> quadratic</em> function f(x) at two points. In this case, we must solve the following <em>second order</em> polynomial:
k · x² + 4 · x - 3 - g(x) = 0
k · x² + 4 · x - 3 - 2 · x + 7 = 0
k · x² + 2 · x + 4 = 0
In this case, the discriminant of the equation described above must be <em>positive</em>:
2² - 4 · k · 4 > 0
4 - 16 · k > 0
4 > 16 · k
16 · k < 4
k < 1/4
By using the definition of <em>second order</em> polynomials and the discriminant from <em>quadratic</em> formula, we conclude that the values of k must be less than 1/4.
To learn more on quadratic equations: brainly.com/question/17177510
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