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3 years ago

10

11) Original price of a lizard: $39.99 Discount: 40% Tax: 6%

1 answer:

denis23 [38]3 years ago

3 0

Answer:

16.9

Step-by-step explanation:

.......ur welcome..........

40% of 39.99=15.95

6% of 15.95= 0.95

15.95 × 0.95=16.9

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Answer the question in the picture.

steposvetlana [31]

Answer: 6

Remember: 0.3 repeated = $\frac{1}{3}$

$3 \frac{2}{3} + 2 \frac{1}{3} = 5\frac{3}{3}\\\\5\frac{3}{3} = 6$

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3 years ago

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What is the equation of a horizontal line that has a y-intercept of 3.5?

beks73 [17]

First, recall that the equation of a line is

y = mx+b

where

m = slope
b = y-int

The key to this question is the details :

Horizontal line ---> This tells you that your slope is 0

y-int = 3.5 -----> In the equation above, b=3.5

Therefore,

y = 0x + 3.5
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3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

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2 years ago

Let f(y) = y^4 - 3y^3 + y - 3 and g(y) = y^3 + 7y^2 - 2. Find f(y) + g(y). Write your answer as a polynomial with terms of decre

Anarel [89]

<h3>Answer: y^4 - 2y^3 + 7y^2 + y - 5</h3>

Work Shown:

h(y) = f(y) + g(y)

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h(y) = y^4 - 3y^3 + y - 3 + y^3 + 7y^2 - 2

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h(y) = y^4 - 2y^3 + 7y^2 + y - 5

This is a fourth degree polynomial (aka quartic).

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2 years ago

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Paul [167]

3% of 96% i think so

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