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Ilya [14]
3 years ago
9

Find the surface area and show work

Mathematics
1 answer:
Law Incorporation [45]3 years ago
7 0

Answer: 1,270in^2

Step-by-step explanation:

The surface area of a rectangle can be calculated with:

Area_{rectangle}=lenght*width

The surface area of a trapezoid can be calculated with:

Area_{trapezoid}=\frac{height}{2}(Larger\ base+Smaller\ base)

Calculate the area of the base, wich is a rectangle:

A_{1}=(34in)(15in)=510in^2

There are two equal rectangles, therefore, multiply the area of any of them by 2:

A_{2}=2(15in)(13in)=390in^2

Calculate the area of the other rectangle:

A_{3}=(15in)(10in)=150in^2

There are two equal trapezoids, therefore, multiply the area of any of them by 2:

A_4=\frac{2(5in)}{2}(34in+10in)=220in^2

Therefore, the surface area will be the sum of all the areas calculated:

SA=A_1+A_2+A_3+A_4\\\\SA=510in^2+390in^2+150in^2+220in^2\\\\SA=1,270in^2

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Answer:

The values are:

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  • b = -6
  • c = -7

Step-by-step explanation:

Given:

  • P = (x₁, y₁, z₁) = (1, 2, b)  
  • Q =  (x₂, y₂, z₂) = (c, -7, 4)  
  • m = R = (x, y, z) = (-3, a, -1)

To Determine:

a = ?

b = ?

c = ?

Determining the values of a, b, and c

Using the mid-point formula

m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)

  • As the point R(-3, a, -1) is the midpoint of the line segment jointing the points P(1,2,b)  and Q(c,-7,4), so
  • m = R = (x, y, z) = (-3, a, -1)

Using the mid-point formula

m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)

given

(x₁, y₁, z₁) = (1, 2, b) = P

(x₂, y₂, z₂) = (c, -7, 4) = Q

m = (x, y, z) = (-3, a, -1) = R

substituting the value of (x₁, y₁, z₁) = (1, 2, b) = P,   (x₂, y₂, z₂) = (c, -7, 4) = Q, and m = (x, y, z) = (-3, a, -1) = R in the mid-point formula

m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)

\left(x,\:y,\:z\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)

as (x, y, z) = (-3, a, -1), so

\left(-3,\:a,\:-1\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)

<u>Determining 'c'</u>

-3 = (1+c) / (2)

-3 × 2 = 1+c

1+c = -6

c = -6 - 1

c = -7

<u>Determining 'a'</u>

a = (2+(-7)) / 2

2a = 2-7

2a = -5

a = -5/2

<u>Determining 'b'</u>

-1 = (b+4) / 2

-2 = b+4

b = -2-4

b = -6

Therefore, the values are:

  • a = -5/2
  • b = -6
  • c = -7
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