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otez555 [7]
3 years ago
14

How much lesss tha 10kg is 5 and 1\2 kg

Mathematics
1 answer:
34kurt3 years ago
7 0

(10) minus (5-1/2)  =  4-1/2 .
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Easy one - giving brainly if correct - show work.<br>answer as many as you can!​
Burka [1]

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3 years ago
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How do you find the area of this composite figure?
Yanka [14]
Split the shape into smaller shapes, (see attachment)
find the area of the split shapes. So first find the area of the triangles
A = 1/2bh
A = 1/2*2*3
A = 1/2*6
A = 3
so that is the area of one triangle. the area of the other is
A = 1/2*4*3
A = 1/2 * 12
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now find the area of the rectangle
A = l*w
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3 years ago
The temperature was –3o C last night. It is now –4o C. What was the change in temperature?
Yuki888 [10]

Answer: -1

Step-by-step explanation: So if the Temperature last night was at -3o C and now it is -4o C it went down by 1 but dont forget the negative symbol.-1

you can think like this: -3-4=-1

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4 years ago
Which of these sets could represent the side lengths of a right triangle?
Jlenok [28]

Answer:

{6, 8, 10} is a set which represents the side length of a right triangle.

Step-by-step explanation:

In a right triangle:

(Base)^{2}  + (Perpendicular)^{2}   = (Hypotenuse)^{2}

Now, in the given triplets:

(a) {4, 8, 12}

Here, (4)^{2}  + (8)^{2}   = 16 + 64  = 80\\\implies H = \sqrt{80}  =  8.94

So, third side of the triangle   8.94 ≠ 12

Hence,  {4, 8, 12} is NOT a triplet.

(b) {6, 8, 10}

Here, (6)^{2}  + (8)^{2}   = 36 + 64  = 100\\\implies H = \sqrt{100}  =  10

So, third side of the triangle  10

Hence,  {6, 8, 10} is  a triplet.

(c) {6, 8, 15}

Here, (6)^{2}  + (8)^{2}   = 36 + 64  = 100\\\implies H = \sqrt{100}  =  10

So, third side of the triangle  10  ≠ 15

Hence,  {6, 8, 15} is  NOT a triplet.

(d) {5, 7, 13}

Here, (5)^{2}  + (7)^{2}   = 25 + 49  = 74\\\implies H = \sqrt{74}  =  8.60

So, third side of the triangle  8.60  ≠ 13

Hence, {5, 7, 13} is  NOT a triplet.

4 0
4 years ago
Consider the following statement. ∀ integer d, if 6 d is an integer then d = 3. Which of the following is a negation for the sta
omeli [17]

Answer:

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

Step-by-step explanation:

If 6d is an integer, then d = 3

Let's divide the statement into two:

Let "If 6d is an integer" be p and "then d = 3" be q.

The statement is a conditional statement. Therefore, we have

p ⇒ q

The negation of p ⇒q, ¬(p ⇒ q) ≡ p ∧ ¬q

I have attached an image proving the above.

Using this: ¬(p ⇒ q) ≡ p ∧ ¬q

Then, we leave p as it is and negate q.

P is "if 6d is an integer"

q is "then d = 3," hence ¬q is "then d ≠ 3."

Therefore, the negation of "If 6d is an integer, then d = 3" is "If 6d is an integer, then d ≠ 3."

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

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3 years ago
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