How much lesss tha 10kg is 5 and 1\2 kg

Katen [24]

7.

One way to figure this out is to go from 2-10, and multiply them by them self each other to see what number works.

Another way is to use a calculator and the square root button.

Hope that helps!

8 0

3 years ago

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raul bought 2 packs of erasers he found 2 erasers in his backpack now raul has 8 erasers were in each pack?

r-ruslan [8.4K]

There was 3 erasers in each pack because 2 times 3 is 6 plus 2 equals 8. so there are 3 in each pack.

7 0

3 years ago

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Someone please help me

Lilit [14]

<h3>Answer:</h3>

C. (9x -1)(x +4) = 9x² +35x -4
B. 480
A. P(t) = 4(1.019)^t

Step-by-step explanation:

1. See the attachment for the filled-in diagram. Adding the contents of the figure gives the sum at the bottom, matching selection C.

2. If we let "d" represent the length of the second volyage, then the total length of the two voyages is ...

... (d+43) + d = 1003

... 2d = 960 . . . . . . . subtract 43

... d = 480 . . . . . . . . divide by 2

The second voyage lasted 480 days.

3. 1.9% - 1.9/100 = 0.019. Adding this fraction to the original means the original is multiplied by 1 +0.019 = 1.019. Doing this multiplication each year for t years means the multiplier is (1.019)^t.

Since the starting value (in 1975) is 4 (billion), the population t years after that is ...

... P(t) = 4(1.019)^t

7 0

3 years ago

Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

zloy xaker [14]

Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>

7 0

3 years ago

A bag contains 13 red bulbs,5 white bulbs and some green bulbs. a bulb is selected at random from the bag. the probability of se

maw [93]

1. There are 6 green bulbs because
13+5=18*1/3=6 green bulbs
2. The probability of getting a red bulb is 15/8
Hope it helps you!!!!

4 0

3 years ago