Answer:
Explanation: a) Resistance, R = 200 ohms; Voltage= 12 volts
Current, I =V/R = 12/200 = 0.06 A
rms current, i = 0.06/√2 = 0.06 X 0.707 = 0.042 A
rms voltage, v = i*R = 0.042 X 200 = 8.48volts
b) Capacitive reactance, Xc = 120/0.042 = 2.86 kilo ohms
Xc = 1/2πfc
Capacitor, c = 1/2πfXc = 1/( 2 x 3.142 x 60 x 2.86 10∧3) = 1/1078334.4 =0.93 micro Farad
c) Maximum reverse voltage, Vr = ( 12 - 0.7) volt = 11.3volts
d) Average current, Ia = 0.7/200 = 0.0035 A
e) Peak diode current, Io = (0.06 + 0.0035) A = 0.064 A