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lesya [120]
3 years ago
13

Which is an example of a subsystem and system relationship?

Engineering
1 answer:
Zanzabum3 years ago
6 0

The example of a subsystem and system relationship is option

A) mechanical toggle, Xbox controller

Explanation:

  • Controls and Controllers are known as the mechanical, electro-mechanical, or electronic devices which are used to  input signals to change the conditions or values which are in processes or access to buildings, operators, gated areas, etc.
  • When you press and hold the given Shift button, these buttons which are chosen becomes an alternate inputs.
  • Normally, there are three controllers(PID) which are used in any of the process industries inorder to maintain and control the required setpoint.
  • an example of a subsystem and system relationship is a mechanical toggle, Xbox controller
  • Controllers improve the steadiness and state of accuracy by decreasing the steady state error. When the steady state accuracy gets better, the stability also improves.
  • Controllers are also used to help in reducing the unwanted offsets which are produced by the system.

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Answer:

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Explanation:

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Explanation:

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t is desired to produce aligned carbon fiber-epoxy matric composite having a longitudinal tensile strength of 800 MPa. Given (a)
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Answer:

The value of critical length = 3.46 mm

The value of volume of fraction of fibers = 0.43

Explanation:

Given data

\sigma_{T} =  800 M pa

D = 0.017 mm

L = 2.3 mm

\sigma_{f} = 5500 M pa

\sigma_{m} = 18 M pa

\sigma_c = 13.5 M pa

(a) Critical fiber length is given by

L_{c} = \sigma_{f} (\frac{D}{2 \sigma_{c} } )

Put all the values in above equation we get

L_{c} =5500 (\frac{0.017}{(2) (13.5)} )

L_{c} = 3.46 mm

This is the value of critical length.

(b).Since this  critical length is greater than fiber length Than the volume fraction of fibers is given by

V_{f} = \frac{\sigma_T - \sigma_m}{\frac{L\sigma_c}{D} - \sigma_m }

Put all the values in above formula we get

V_{f} = \frac{800-18}{\frac{(2.3)(13.5)}{0.017} - 18 }

V_{f} = 0.43

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3 years ago
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Black_prince [1.1K]

Answer:

  use the percentage error relation

Explanation:

The percentage error in anything is computed from ...

  %error = ((measured value)/(accurate value) -1) × 100%

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The difficulty with voltage measurements is that the "accurate value" may be hard to determine. It can be computed from the nominal values of circuit components, but there is no guarantee that the components actually have those values.

Likewise, the measuring device may have errors. It may or may not be calibrated against some standard, but even measurement standards have some range of possible error.

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