When operating a crane, which of the following is an important safety precaution? Select all that apply.
1 answer:
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Given Information:
Balanced Y-Y three phase circuit
Phase Voltage = Van = 120 < 10° V
Load Impedance = Zy = 20 +j15 Ω = 25 < 36.86° Ω
Required Information:
Load Voltages = Vab, Vbc, Vca = ?
Line currents = Ia, Ib, Ic = ?
Answer:
Vab = 208 < 40°
Vbc = 208 < -80°
Vca = 208 < 160°
Ia = 4.8 < -26.86°
Ib = 4.8 < -146.86°
Ic = 4.8 < 93.14°
Explanation:
Since it is balanced 3 phase system, all phases have equal magnitude and 120° phase shift
Van = 120 < 10° V
Vbn = 120 < -110° V
Vcn = 120 < 130° V
In a Y connected system, the phase voltage and line voltage are related as
Vab = (Van) <+30°
Vab = *120<10°+30°
Vab = 208 < 40°
Vbc = 208 < -80°
Vca = 208 < 160°
In a Y connected circuit, Iphase = Iline
Ia = Van/Zy
Ia = 120 < 10°/25 < 36.86°
Ia = 4.8 < -26.86°
Ib = 4.8 < -146.86°
Ic = 4.8 < 93.14°
Answer:
The two values of x are 2n*pi + pi/12 and 2n*pi -5pi/12
Explanation:
The given equation is
Sin x +√3 Cosx= √2
Upon dividing the equation by 2 we get
Sin()*Sinx + Cos(
)*Cosx =
This makes the formula of
CosACosB + SinASinB = Cos(A-B)
Cos(x-) =
cos(x- pi/6) = cos(pi/4)
upon writing the general equation we get
x-pi/6 = 2n*pi ± pi/4
x = 2n*pi ± pi/4 -pi/6
so we will have two solutions
x = 2n*pi + pi/4 -pi/6
= 2n*pi + pi/12
and
x = 2n*pi - pi/4 -pi/6
= 2n*pi -5pi/12
Therefore the two values of x are 2n*pi + pi/12 and 2n*pi -5pi/12.
Answer:
6.30 miles/hour
Explanation:
Newton's second law applies here. In simple terms:
where F = Force (Thrust) in N
a = acceleration (m/s²)
The acceleration can be given by rearranging the formula to give:
=