The spring constant is 147 N/m
Given the mass of the block is 2.00 kg , the mass of the body is 300 g and the length of the spring is 2.00 cm
We need to find the spring constant
A spring is an object that can be deformed by a force and then return to its original shape after the force is removed.
The force required to stretch an elastic object such as a metal spring is directly proportional to the extension of the spring
We know that F = kx
300(9.8)= k (0.02)
k = 147.15 N/m
Rounding off to the nearest is 147N/m
The spring constant is 147N/m
Learn more about Hooke's law here
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Answer:
ok so youll tell me when you have problems
We can answer this problem using Ampere’s Law:
<span>Bh = μoNI </span>
Where:
B = Magnetic Field
h = coil length
<span>μo = permeability =4π*10^-7 T·m/A </span>
N = number of turns
I = current
It is given that B=0.0015T, I=1.0A, h=10 cm =
0.1m<span>
Use Ampere's law to find # turns:
Which can be rewritten as:
<span>N = Bh/μoI </span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0)
N = 119.4
</span>
<span>Answer:
119.4 turns</span>
Answer:
P₂ = 370 kPa
Explanation:
Boyle's law: States that the volume of a given mass of gas is inversely proportional to its pressure provided the temperature remains constant. It can be expressed mathematically as,
P₁V₁ = P₂V₂................ Equation 1
Where P₁ = Initial Pressure, V₁ = Initial volume, P₂ = Final Pressure, V₂ = Final Volume.
Making P₂ The subject of the equation above,
P₂ = P₁V₁/V₂..................... equation 2
Substituting these vaues into equation 2,
Where P₁ = 163 kPa = 163000 pa, V₁ = 10 L, V₂ = 4.4 L.
P₂ = 163000(10)/4.4
P₂ = 370454.55 Pa
P₂ = 370000 Pa
P₂ = 370 kPa To 3 significant figure.
Therefore Final pressure = 370 kPa
