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irina [24]
4 years ago
12

How many turns should a 10-cm long solenoid have if it is to generate a 1.5 x 10-3 t magnetic field on 1.0 a of current?

Physics
1 answer:
stepan [7]4 years ago
3 0

We can answer this problem using Ampere’s Law:

<span>Bh = μoNI </span>

Where:

B = Magnetic Field

h = coil length

<span>μo = permeability =4π*10^-7 T·m/A </span>

N = number of turns

I = current

It is given that B=0.0015T, I=1.0A, h=10 cm = 0.1m<span>

Use Ampere's law to find # turns: 
Which can be rewritten as: 
<span>N = Bh/μoI </span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0) 
N = 119.4 

</span>

<span>Answer: 119.4 turns</span>

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