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Lina20 [59]
2 years ago
10

An object is travelling at a velocity of 5m/s to the right for 5 seconds. If NO forces are applied to the object, what will the

velocity of the object be after 5 seconds.
Physics
1 answer:
creativ13 [48]2 years ago
6 0

Answer:

Below

Explanation:

We can use this formula to find the final velocity of the object :

     vf = vi + at

Now, because no force is applied to the object, the acceleration of this object will be 0 according to Newton's 1st law!

     vf = 5m/s + (0)(5)

     vf = 5 m/s

Hope this helps!

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Help please! This question is driving me crazy
Varvara68 [4.7K]

Answer:

-10.8°, or 10.8° below the +x axis

Explanation:

The x component of the resultant vector is:

x = 3.14 cos(30.0°) + 2.71 cos(-60.0°)

x = 4.07

The y component of the resultant vector is:

y = 3.14 sin(30.0°) + 2.71 sin(-60.0°)

y = -0.777

Therefore, the angle between the resultant vector and the +x axis is:

θ = atan(y / x)

θ = atan(-0.777 / 4.07)

θ = -10.8°

The angle is -10.8°, or 10.8° below the +x axis.

3 0
3 years ago
Will you still get tan with sunscreen on
WARRIOR [948]
No, wearing sunscreen won't let you tan. The whole purpose of sunscreen is to protect your skin from sun rays. You can start to become tan if you dont have much sunscreen on - its happened to me.
5 0
3 years ago
Visible light includes all of the
krek1111 [17]

Answer:Visible light is a small part of the electromagnetic spectrum. The spectrum covers everything from gamma rays, x-rays, visible light, infrared, microwave and radio waves. Each part of the spectrum, including the different colors of visible light, have different wavelengths (the space between each wave).

Explanation:

6 0
3 years ago
Fighter jet starting from airbase A flies 300 km east , then 350 km at 30° west of north and then 150km north to arrive finally
Tems11 [23]
A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North.
It means : at 60° North of West. So the distance from the final point to the line AM is :
350 · cos 60° = 350 · 0.866 = 303.1 km
Let`s assume that there is a line N on AM.
AN = 125 km and NM = 175 km.
And finally jet fighter flies 150 km North to arrive at airbase B.
NB = 303.1 + 150 = 453.1 km
Then we can use the Pythagorean theorem.
d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km
Also foe a direction: cos α = 125 / 470 = 0.266
α = cos^(-1) 0.266 = 74.6°
90° - 74.6° = 15.4°
Answer: The distance between the airbase A and B is 470 km.
Direction is : 15.4° East from the North. 
4 0
3 years ago
I NEED HELP ASAP!!!
Savatey [412]
I think option C is correct..hope it helps
3 0
2 years ago
Read 2 more answers
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