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a_sh-v [17]
3 years ago
5

A researcher is interested in determining the average length and weight of loblolly pine tree needles in the southeast United St

ates. Will the data be obtained through observation or experimentation?
Physics
2 answers:
Anna [14]3 years ago
8 0

Answer:

Experimentation

Explanation:

The loblolly pine tree is a member of the yellow pine group which is grown in plantations for commercial production of timber.The tree itself can reach a height of 40 meters with a truck of 1 meter in diameter.Pines have long needle-like leaves held in bundles. A researcher can measure the length of the needles, count the number of needles in a bundle, and measure the length of the sheath.Loblloly pine needles measure up to 17 cm long.The researcher can also weigh a bundle and determine the weight of the needles.This is field experiment that will require a measuring device for weight and length so observation alone won't provide the needed data.

olga55 [171]3 years ago
8 0

Answer:

The correct answer will be- both observation and experimentation

Explanation:

The determination of length and weight of the pine trees of the forest can be determined by the scientific method.

The observation must be done to measure the length and weight of the trees using the instruments whereas the calculation of the measurement must be done through a systematic approach to calculating the average.

Both observation and experimentation are steps of the scientific method which can lead to the answer therefore,  both observation and experimentation are correct.

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Why can the structure of the solar system be compared to soap bubbles?
lukranit [14]
Because the universe is sort of like the surface of a balloon just like soap bubbles. The reason for this, is because of all the clusters and superclusters that are found within the bubble walls. Hope that helps!
7 0
3 years ago
A horizontal board of negligible thickness and area 2.0 m2 hangs from a spring scale that reads 80 N when a 4.0 m/s wind moves b
ki77a [65]

Answer:

Scale reading for no wind W'=60N

Explanation:

From the question we are told that

Area A= 2.0 m^2

Weight of board W=80

Velocity V=4.0m/s

Density of air \delta= 1.25 kg/m3 .

Generally the equation for pressure difference by Bernoulli equation is mathematically given by

  dP=\frac{1}{2}pv^2

  dP=10Pa

Generally force acting on the board by air is mathematically given by

F=\triangle PA

F=(10)2=>20N

Therefore

Scale reading for no wind W'

W'=W-F\\W'=80-20

W'=60N

Scale reading for no wind W'=60N

6 0
3 years ago
5.) How could we have improved this activity to be more precise?<br><br>ball on ramp ​​
AleksAgata [21]

Explanation:

I don't understand this question

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7 0
3 years ago
A cord is wrapped around the rim of a solid uniform wheel 0.300 m in radius and of mass 8.00 kg. A steady horizontal pull of 34.
disa [49]

Answer:

A. α = 94.4 rad/s

B. a = 28.32 m/s

C. N = 34N

D. α = 94.4 rad/s

    a = 28.32 m/s

     N =  44.4  N

Explanation:

part A:

using:

∑T = Iα

where T is the torque, I is the moment of inertia and α is the angular momentum.

firt we will find the moment of inertia I as:

I = \frac{1}{2}MR^2

Where M is the mass and R is the radius of the wheel, then:

I = \frac{1}{2}(8 kg)(0.3 m)^2

I = 0.36 kg*m^2

Replacing on the initial equation and solving for α, we get::

∑T = Iα

Fr = Iα

34 N =  0.36α

α = 94.4 rad/s

part B

we need to use this equation :

a = αr

where a is the aceleration of the cord that has already been pulled off and r is the radius of the wheel, so replacing values, we get:

a = (94.4)(0.3 m)

a = 28.32 m/s

part C

Using the laws of newton, we know that:

N = T

where N is the force that the axle exerts on the wheel part and T is the tension of the cord

so:

N = 34N

part D

The anly answer that change is the answer of the part D, so, aplying laws of newton, it would be:

-Mg + N +T = 0

Then, solving for N, we get:

N = -T+Mg

N = -34 + (8 kg)(9.8)

N =  44.4  N

6 0
3 years ago
How does the energy moves from the suns core to the photosphere?
Minchanka [31]

Answer: Energy from the core travels by radiation through the radiative

zone, then by convection through the convection zone.

Explanation:

4 0
3 years ago
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