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3 years ago

-6 + 1/4x + 3(1/4x + 6)

Mathematics

2 answers:

ryzh [129]3 years ago

8 0

Answer:

12+x

Step-by-step explanation:

=-6+1/4x+3(1/4x+6)

=-6+x/4+3(x/4+6)

=-6+x/4+3×(x+24/4)

=-6+x/4+3x+72/4

=-24+x+3x+72/4

=48+4x/4

=4(12+x) /4

=12+x.

hence, answer is 12+x..

Andrei [34K]3 years ago

8 0

Answer:

1x + 12

Step-by-step explanation:

-6 + 1/4x + 3(1/4x + 6)

-6 + 1/4x + 3/4x + 18

-6 + 1x + 18

1x + 12

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3 years ago

Roger is building a storage shed with wood blocks that are in the shape of cubic prisms. Can he build a shed that is twice as hi

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Complete question is;

Roger is building a storage shed with wood blocks that are in the shape of cubic prisms. Can he build a shed that is twice as high as it is wide?

A. Yes. For every block of width, he could build two blocks high.

B. Yes. He could use half as many blocks for the height as the width.

C. There is no way to determine if he can do this.

D. No, it is not possible to do this

Answer:

A. Yes. For every block of width, he could build two blocks high.

Step-by-step explanation:

We are told that the wood blocks are in the shape of cubic prisms.

Now, cube shapes means that all sides are equal.

Now, if he divides the cube into 2, he can use one have to add to the top to make the height double since the sides are equal.

Thus, the height will now be twice a side of the cubic prism.

Thus, he can build a shed twice as high as its width.

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3 years ago

Read 2 more answers

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa

KengaRu [80]

Answer:

a. 0.5 or 50%

b. 0.496 or 49.6%

c. 0.8185 or 81.85%

d. Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm

e. 0.0252 or 2.52%

f. The qualifying speed would be 47.4 wpm.

Step-by-step explanation:

a. Let's find the z-score this way:

μ = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

p (z=0) = 0.5 or 50%

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

p (z = -0.01) = 0.496 or 49.6%

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

In consequence,

p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

p = 0.0252 or 2.52%

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

The qualifying speed would be 47.4 wpm.

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Answer:

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