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Sati [7]
3 years ago
10

I need help simplifying both of these. thank you!

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0
<h3>Answer:</h3>
  1. -100x +100; 3
  2. 5x +81; 162
<h3>Step-by-step explanation:</h3>

The distributive property is your friend. It tells you ...

  a(b + c) = ab + ac

It can also be used to simplify the product of binomials (or other polynomials).

  (a +b)^2 = (a +b)(a +b) = a(a +b) + b(a +b) = a^2 +ab +ab +b^2

  (a +b)^2 = a^2 +2ab + b^2 . . . . . . . worth remembering

1. (x -10)^2 -x(x +80) = (x^2 -20x +100) +(-x^2 -80x)

  = -100x +100 . . . . . . simplified form

For the purposes of calculation, it can be easier to factor out 100:

  = 100 (1 -x)

Then for x = 0.97

  = 100(1 -0.97) = 100(0.03) = 3

___

2. (2x +9)^2 -x(4x +31) = (4x^2 +36x +81) -4x^2 -31x = 5x +81

For x = 16.2, this is ...

  5(16.2) +81 = 81 +81 = 162

_____

The purpose of the attachment is to show the evaluation is correct.

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4/5 divided by 1/3 plus 1/5 minus 3/5
r-ruslan [8.4K]

Answer:

  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}

so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}

join  \frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}

so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

=-\frac{4}{5\cdot \frac{1}{15}}

\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}

so

=-\frac{4}{\frac{1}{3}}

\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

=-\frac{12}{1}

\mathrm{Apply\:rule}\:\frac{a}{1}=a

=-12

Therefore

                  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

4 0
3 years ago
How to factor 6n2 - 6n - 12
alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

6n^2-6n-12 = 6(n^2-n-2)

We can set this equal to 0 and factor by using the quadratic formula which is:

x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

So, let's do just that:

6(n^2-n-2) = 0

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}

\frac{-1 \pm \sqrt{9} }{2} = {1, -2}

So, we can write this as:

6n^2 - 6n - 12 = 6(n-1)(n+2)

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

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#11 i
Paraphin [41]

The area of a shape is the amount of space a shape can occupy, while the perimeter is the sum of its lengths.

  • <em>The perimeter is </em>18 + 3\sqrt 5 + 3\sqrt 2<em>units</em>
  • <em>The area of the sanctuary is 27 square units</em>

We have:

A = (5,7)\\B=(8, 7)\\C=(8, 1)\\D=( 1, 1)\\E=( 1, 4)\\F= ( 5,4)

<u>Perimeter</u>

See attachment for the layout of the sanctuary

BC = \sqrt{(8 - 8)^2 + (7 - 1)^2} = 6

EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4

FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3

From the attachment, the sides are

<em>AB, BF, FC, CD, DE and EA</em>

Start by calculating the length of each side using the following distance formula:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_2)^2}

So, we have:

AB = \sqrt{(5 - 8)^2 + (7 - 7)^2} = 3

BF = \sqrt{(8 - 5)^2 + (7 -1)^2} = \sqrt{45} = 3\sqrt 5

FC = \sqrt{(8 - 5)^2 + (1 -4)^2} = \sqrt{18} = 3\sqrt 2

CD = \sqrt{(8 - 1)^2 + (1 - 1)^2} = 7

DE = \sqrt{(1 - 1)^2 + (1 - 4)^2} = 3

EA = \sqrt{(1 - 5)^2 + (4 -7)^2} = 5

So, the perimeter (P) is:

P = AB + BF + FC + CD + DE + EA

P = 3 + 3\sqrt 5 + 3\sqrt 2 + 7 + 3 + 5

P = 18 + 3\sqrt 5 + 3\sqrt 2

<em>Hence, the perimeter is </em>18 + 3\sqrt 5 + 3\sqrt 2<em>units</em>

<u />

<u>Area</u>

To calculate the area, we need to divide the sanctuary into three.

  1. <em>Triangle ABF</em>
  2. <em>Triangle EFA</em>
  3. <em>Trapezium CDEF</em>

The area of ABF is:

Area = \frac 12 \times AB \times FA

Where:

AB = 3

FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3

Area = \frac 12 \times 3 \times 3

Area = \frac 92

The area of EFA is:

Area = \frac 12 \times EF \times FA

Where:

FA = 3

EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4

So:

Area = \frac 12 \times 4 \times 3

Area = 6

The area of CDEF is:

Area = \frac 12(CD + EF) \times DE

Where

CD = 7

EF = 4

DE = 3

So, we have:

Area = \frac 12 (7 + 4) \times 3

Area = \frac 12 \times 11 \times 3

Area = \frac {33}2

So, the area of the sanctuary is:

Area = \frac 92 + 6 + \frac {33}2

Area = \frac {9 +12 + 33}2

Area = \frac {54}2

Area = 27

<em>Hence, the area of the sanctuary is 27 square units</em>

Read more about areas and perimeters at:

brainly.com/question/11957651

8 0
3 years ago
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